Sql 如何确定两个查询中的值之间的比率？

我有两个疑问

 SELECT
    COUNT(DISTINCT s.KliRC) Celkem
    ,r.Region
FROM dbo.Smlouvy s
        JOIN CS_OZ oz       ON oz.KodOZ = s.KodOZ
        JOIN CS_Regiony r   ON r.KodRegionu = oz.KodRegionu   
GROUP BY
    r.Region

-- +

SELECT
    COUNT(DISTINCT s.KliRC) Solus
    ,r.Region
FROM dbo.SolusDetaily sd
    JOIN dbo.Smlouvy s      ON sd.CisloZadosti    = s.CisloSmlouvy    
        JOIN CS_OZ oz       ON oz.KodOZ = s.KodOZ
        JOIN CS_Regiony r   ON r.KodRegionu = oz.KodRegionu
GROUP BY
    r.Region

我想在（Count）字段中确定它们之间的比率。

---

我尝试了使用cte实现所有的联合，但没有达到预期的效果。

尝试类似的方法

select Region,(Celkem * 1.0) /sum(Celkem)over() as Ratio
(
selcet Region, COUNT(DISTINCT s.KliRC) Celkem
from ..
Union All
selcet Region, COUNT(DISTINCT s.KliRC) Solus
from ..
) A

---

我认为您可以

内部联接
两个子查询

使用
NULLIF（c.Celkem，0）
避免被零除的错误

SELECT s.Region, (s.Solus * 1.0)/NULLIF(c.Celkem,0) as Ratio
FROM
(
    SELECT
            COUNT(DISTINCT s.KliRC) Solus
            ,r.Region
    FROM dbo.SolusDetaily sd
        JOIN dbo.Smlouvy s      ON sd.CisloZadosti    = s.CisloSmlouvy    
            JOIN CS_OZ oz       ON oz.KodOZ = s.KodOZ
            JOIN CS_Regiony r   ON r.KodRegionu = oz.KodRegionu
    GROUP BY
        r.Region
) s
INNER JOIN 
(
    SELECT
            COUNT(DISTINCT s.KliRC) Celkem
            ,r.Region
    FROM dbo.Smlouvy s
            JOIN CS_OZ oz       ON oz.KodOZ = s.KodOZ
            JOIN CS_Regiony r   ON r.KodRegionu = oz.KodRegionu   
    GROUP BY
        r.Region
) c on  s.Region = c.Region

您可以使用通用表表达式：

    with t1 as
    (
    SELECT
        COUNT(DISTINCT s.KliRC) Celkem
        ,r.Region Region
    FROM dbo.Smlouvy s
            JOIN CS_OZ oz       ON oz.KodOZ = s.KodOZ
            JOIN CS_Regiony r   ON r.KodRegionu = oz.KodRegionu   
    GROUP BY
        r.Region
    ),
    with t2 as
    (

    SELECT
        COUNT(DISTINCT s.KliRC) Solus
        ,r.Region Region
    FROM dbo.SolusDetaily sd
        JOIN dbo.Smlouvy s      ON sd.CisloZadosti    = s.CisloSmlouvy    
            JOIN CS_OZ oz       ON oz.KodOZ = s.KodOZ
            JOIN CS_Regiony r   ON r.KodRegionu = oz.KodRegionu
    GROUP BY
        r.Region
    ) 
    -- get ratio
    select t1.region , t1.Celkem /t2.Solus as ratio
    from t1
    join t2 on t1. Region = t2.Region

你能添加你的联合所有脚本吗？它们之间的定量（计数）
是什么意思？您能举个例子吗？两个查询是否总是返回相同的
区域列表
s，或者一个查询有时是否有另一个查询没有的
区域
？