为什么在同一个表上使用不同的组和计数的3个内部联接不能使用sqlite？

我有一个包含历史迁移数据的表。它包含移民来自的国家、地区和城镇的字段。我想得到一个表格，显示每个城镇有100个或更多数据集条目的条目数，以及提及的地区和国家，以及该地区和国家的数据集条目数

如果我按城镇进行简单分组，则地区和国家/地区的计数将始终在一个城镇的组内，因此我无法计算地区和国家/地区的条目总数

country | sum_country | region  | sum_region | town   | sum_town 
Germany | 324,213     | Prussia | 324,213    | Berlin | 324,213

因此，我尝试使用不同分组的内部联接，并对相同的数据表进行计数（使用不同的别名）

这在国家和地区的两个内部连接中运行良好

country | sum_country | region  | sum_region | town   | sum_town 
Germany | 4,546,321   | Prussia | 864,345    | Berlin | 324,213
Germany | 4,546,321   | Unknown | 3,845,321  | Berlin | 640,139

结果我发现我有很多城镇在不同的国家或地区背景下被提及（因为历史数据不太一致）。为了了解这种现象的数量，我想集成第三个内部连接，以计算任何国家/地区/城镇群中每个城镇的条目总数。结果应该如下所示：

country | sum_country | region  | sum_region | town   | sum_town | sum_total_town
Germany | 4,546,321   | Prussia | 864,345    | Berlin | 324,213  | 964,352
Germany | 4,546,321   | Unknown | 3,845,321  | Berlin | 640,139  | 964,352

在DB Browser for SQLite中尝试此查询时，我收到一条错误消息，上面说：

'near "(": syntax error:' 

以下是我的代码，它不起作用：

select a.country, c.summe_land, a.last_province, e.summe_region, a.last_town, g.summe_stadt count (a.last_town) as summe_kombi
from migrant_data as a 

inner join 
(select b.country, count(b.country) as summe_land 
from migrant_data as b group by b.country) as c 
on a.country = c.country

inner join
(select d.last_province, count(d.last_province) as summe_region
from migrant_data as d group by d.last_province) as e
on a.last_province = e.last_province

inner join
(select f.last_town, count(f.last_town) as summe_stadt
from migrant_data as f group by f.last_town) as g
on a.last_town = g.last_town

group by a.country, c.summe_land, a.last_province, e.summe_region, a.last_town, g.summe_stadt 
having count(a.last_town) >99 
order by c.summe_land desc, e.summe_region desc, count (a.last_town) desc;

我仔细检查了我的第三个内部连接，但它的结构与前两个内部连接完全相同，工作正常。我不知道我应该或不应该把括号放在哪里，也不知道所用括号旁边有什么问题

所以我不知道第三个内部连接有什么问题。我在stackoverflow上找到了各种使用三个内部联接的示例，因此似乎可以聚合三个内部联接。也许我忽略了一些非常简单的事情，我对SQL查询相对来说是新手（实际上我是历史学家）

---

有什么建议吗？谢谢你的关注

你在计数前漏掉了一个逗号（a.last_town）

试用

  select 
    a.country
    , c.summe_land
    , a.last_province
    , e.summe_region
    , a.last_town
    , g.summe_stadt
    , count (a.last_town) as summe_kombi
  from migrant_data as a 
  inner join  (
        select b.country, count(b.country) as summe_land 
        from migrant_data as b group by b.country) as c on a.country = c.country
  inner join (
        select d.last_province, count(d.last_province) as summe_region
        from migrant_data as d 
        group by d.last_province) as e on a.last_province = e.last_province
  inner join  (
        select f.last_town, count(f.last_town) as summe_stadt
        from migrant_data as f 
        group by f.last_town) as g on a.last_town = g.last_town

  group by a.country, c.summe_land, a.last_province, e.summe_region, a.last_town, g.summe_stadt 
  having count(a.last_town) >99 
  order by c.summe_land desc, e.summe_region desc, count(a.last_town) desc;

---

谢谢你的快速回复。逗号起了作用。感谢您提出更好地编写命令的建议，舒尔帮助您查找缺失的逗号。我想我必须找到一个更好地支持sql语法的编辑器。

select 
   a.country
  , c.summe_land
  , a.last_province
  , e.summe_region
  , a.last_town
  , g.summe_stadt count(a.last_town) as summe_kombi
                ^^^ here

from migrant_data as a 
...

  select 
    a.country
    , c.summe_land
    , a.last_province
    , e.summe_region
    , a.last_town
    , g.summe_stadt
    , count (a.last_town) as summe_kombi
  from migrant_data as a 
  inner join  (
        select b.country, count(b.country) as summe_land 
        from migrant_data as b group by b.country) as c on a.country = c.country
  inner join (
        select d.last_province, count(d.last_province) as summe_region
        from migrant_data as d 
        group by d.last_province) as e on a.last_province = e.last_province
  inner join  (
        select f.last_town, count(f.last_town) as summe_stadt
        from migrant_data as f 
        group by f.last_town) as g on a.last_town = g.last_town

  group by a.country, c.summe_land, a.last_province, e.summe_region, a.last_town, g.summe_stadt 
  having count(a.last_town) >99 
  order by c.summe_land desc, e.summe_region desc, count(a.last_town) desc;