Sqlite中的第二页JQM Listview不刷新
我正在开发一个离线应用程序,目前将在我的笔记本电脑上运行。我从Sqlite中提取数据并在listview中显示数据。它在第一页可以正常工作,但是如果我想在第二页显示列表视图数据,它就不能工作。我错过了什么 用于在第一页上显示的工作代码:Sqlite中的第二页JQM Listview不刷新,sqlite,listview,jquery-mobile,jquery-mobile-listview,Sqlite,Listview,Jquery Mobile,Jquery Mobile Listview,我正在开发一个离线应用程序,目前将在我的笔记本电脑上运行。我从Sqlite中提取数据并在listview中显示数据。它在第一页可以正常工作,但是如果我想在第二页显示列表视图数据,它就不能工作。我错过了什么 用于在第一页上显示的工作代码: <!DOCTYPE html> <html> <head> <title>Soccer</title> <meta name="viewport" content="width=device-wi
<!DOCTYPE html>
<html>
<head>
<title>Soccer</title>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://code.jquery.com/mobile/1.2.0/jquery.mobile-1.2.0.min.css">
<script src="https://code.jquery.com/jquery-1.8.2.min.js"></script>
<script src="https://code.jquery.com/mobile/1.2.0/jquery.mobile-1.2.0.min.js"></script>
<script type="text/javascript">
var db = window.openDatabase("ShoufiMobi", "1.0", "Just a Dummy DB", 200000); //will create database Dummy_DB or open it
//function will be called when an error occurred
function errorCB(err) {
alert("Error processing SQL: "+err.code);
}
//function will be called when process succeed
function successCB() {
// alert("success!");
db.transaction(queryDB,errorCB);
}
//select all from SoccerPlayer
function queryDB(tx){
tx.executeSql('SELECT * FROM Mailbox',[],querySuccess,errorCB);
}
function querySuccess(tx,result){
$('#SoccerPlayerList').empty();
$.each(result.rows,function(index){
var row = result.rows.item(index);
$('#SoccerPlayerList').append('<li><a href="#pagetwo"><img src="public_80x80.png"><h3 class="ui-li-heading">'+row['boxname']+'</h3><p class="ui-li-desc">Email '+row['boxstatus']+'</p><span class="ui-li-count">25</span></a></li>');
});
$('#SoccerPlayerList').listview();
}
successCB();
</script>
</head>
<body>
<div data-role="page" id="pageone">
<div data-role="header" data-position="fixed" data-theme="b">
<h1>Soccer Player</h1>
</div><!-- /header -->
<div data-role="content">
<ul id="SoccerPlayerList">
</ul>
</div><!-- /content -->
<div data-role="footer">
<h4>Footer</h4>
</div><!-- /footer -->
</div><!-- /pageone -->
<div data-role="page" id="pagetwo">
<div data-role="header" data-position="fixed" data-theme="b">
<h1>Welcome To My Second Page</h1>
</div>
<div data-role="content">
<a href="#pageone"><h4> hello</h4></a>
</div>
<div data-role="footer">
<h1>Footer Text</h1>
</div>
</div>
</body>
</html>
现在,如果我交换第一页和第二页的内容,我会收到警告:处理SQL:0时出错,并且我会丢失第二页上listview的格式。我错过了什么?
以下是交换页面内容的代码:
<body>
<div data-role="page" id="pageone">
<div data-role="header" data-position="fixed" data-theme="b">
<h1>Soccer Player</h1>
</div><!-- /header -->
<div data-role="content">
<a href="#pagetwo"><h4> hello</h4></a>
</div><!-- /content -->
<div data-role="footer">
<h4>Footer</h4>
</div><!-- /footer -->
</div><!-- /pageone -->
<div data-role="page" id="pagetwo">
<div data-role="header" data-position="fixed" data-theme="b">
<h1>Welcome To My Second Page</h1>
</div>
<div data-role="content">
<ul id="SoccerPlayerList">
</ul>
</div>
<div data-role="footer">
<h1>Footer Text</h1>
</div>
</div>
</body>
非常感谢我让它像这样工作:
<!DOCTYPE html>
<html>
<head>
<title>Soccer</title>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://code.jquery.com/mobile/1.2.0/jquery.mobile-1.2.0.min.css">
<script src="https://code.jquery.com/jquery-1.8.2.min.js"></script>
<script src="https://code.jquery.com/mobile/1.2.0/jquery.mobile-1.2.0.min.js"></script>
<script type="text/javascript">
var db = window.openDatabase("ShoufiMobi", "1.0", "Just a Dummy DB", 200000); //will create database Dummy_DB or open it
$(document).on("pageinit", "#pageone", function () {
//function will be called when an error occurred
function errorCB(err) {
alert("Error processing SQL: "+err.code);
}
//function will be called when process succeed
function successCB() {
// alert("success!");
db.transaction(queryDB,errorCB);
}
//select all from SoccerPlayer
function queryDB(tx){
tx.executeSql('SELECT * FROM Mailbox',[],querySuccess,errorCB);
}
function querySuccess(tx,result){
$('#SoccerPlayerList').empty();
$.each(result.rows,function(index){
var row = result.rows.item(index);
$('#SoccerPlayerList').append('<li><a href="#pagetwo"><img src="public_80x80.png"><h3 class="ui-li-heading">'+row['boxname']+'</h3><p class="ui-li-desc">Email '+row['boxstatus']+'</p><span class="ui-li-count">25</span></a></li>');
});
}
successCB();
}); //on pageinit #pageone
$(document).on("pagebeforeshow", "#pagetwo", function () {
$('#SoccerPlayerList').listview();
});
</script>
</head>
<body>
<div data-role="page" id="pageone">
<div data-role="header" data-position="fixed" data-theme="b">
<h1>Soccer Player</h1>
</div>
<!-- /header -->
<div data-role="content">
<a href="#pagetwo"><h4> hello</h4></a>
</div>
<!-- /content -->
<div data-role="footer">
<h4>Footer</h4>
</div>
<!-- /footer -->
</div>
<!-- /pageone -->
<div data-role="page" id="pagetwo">
<div data-role="header" data-position="fixed" data-theme="b">
<h1>Welcome To My Second Page</h1>
</div>
<div data-role="content">
<a href="#pageone"><h4> Back</h4></a>
<ul id="SoccerPlayerList"></ul>
</div>
<div data-role="footer">
<h1>Footer Text</h1>
</div>
</div>
</body>
</html>
从代码中很难看出何时调用数据库。但是,假设您希望在第1页上进行调用,以便在导航到第2页时调用已经存在,请刷新第2页的pagebeforeshow事件上的listview:
$(document).on("pageinit", "#pageone", function () {
$('#SoccerPlayerList').empty();
$.each(result.rows, function (index, row) {
$('#SoccerPlayerList').append('<li><a href="#pagetwo"><img src="http://lorempixel.com/80/80/technics/' + index + '/"><h3 class="ui-li-heading">' + row['boxname'] + '</h3><p class="ui-li-desc">Email ' + row['boxstatus'] + '</p><span class="ui-li-count">25</span></a></li>');
});
});
$(document).on("pagebeforeshow", "#pagetwo", function () {
$('#SoccerPlayerList').listview();
});
工作