使用swiftyJson解析JSON对象

我从一个API调用得到以下JSON响应（见下文）。我试图检索用户id并将其存储在一个数组中，但似乎无法隔离用户id

这样做的理想方式是什么

{
    "status": "ok",
    "followers": {
        "3": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com"
        },
        "31": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com
        },
        "35": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com
        },
        "37": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com
        },
        "43": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com"
        },
        "47": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com
        },
        "64": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com
        },
        "202": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com
        },
        "357": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com
        },
        "387": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com
        },
        "2328": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com
        },
        "2333": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com
        },
        "2334": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com
        },
        "2371": {
            "username": "username",
            "display_name": "username",
            "mail": "username@domain.com
        }
    },
    "count": 14
}

我可以以字符串和int值的形式检索状态和计数值，但是我很难将id号分开，在这种情况下，id号是

[3,31,35,37,43,47,64202357387232823323342371]

let status = json["status"].stringValue
let count = json["count"].intValue

---

让json[“followers”]作为[String:Any]

提供一个字典。“id”是它的关键。因此根据这个=>

let allIds=let json[“followers”].flatMap（）{$0.0}

非常感谢。这很好用

让json[“followers”]作为[String:Any]

提供一个字典。“id”是它的关键。因此根据这个=>

let allIds=let json[“followers”].flatMap（）{$0.0}

非常感谢。这很好用！