Symfony2:使用Ajax和表单创建相关实体,而不加载所有实体
我们有一个Symfony2应用程序,它允许管理员使用Ajax POST请求将付款记入用户帐户。POST请求发送由Symfony控制器处理的JSON。控制器应创建一个支付实体,对其进行验证并将其持久化。我们希望利用Symfony表单系统的内置验证 例如,id为20的用户获得100p的积分,发布的JSON应该如下所示Symfony2:使用Ajax和表单创建相关实体,而不加载所有实体,symfony,doctrine-orm,Symfony,Doctrine Orm,我们有一个Symfony2应用程序,它允许管理员使用Ajax POST请求将付款记入用户帐户。POST请求发送由Symfony控制器处理的JSON。控制器应创建一个支付实体,对其进行验证并将其持久化。我们希望利用Symfony表单系统的内置验证 例如,id为20的用户获得100p的积分,发布的JSON应该如下所示 {"user":"20","amount":"100","description":"test payment","paymentType":"credit"} 在Symfony端,
{"user":"20","amount":"100","description":"test payment","paymentType":"credit"}
在Symfony端,我们有一个PaymentType表单
class PaymentType extends AbstractType
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add('user', 'entity', [
'class' => 'OurAppBundle\Entity\User',
'choice_label' => 'email',
'multiple' => false,
'expanded' => true,
]);
$builder->add('paymentType', 'choice', [
'choices' => [ 1 => 'credit', 2 => 'debit'],
'choices_as_values' => true,
]);
$builder->add('amount', 'number');
$builder->add('description', 'textarea');
}
支付实体与用户实体相关并包含验证
class Payment
{
const TYPE_CREDIT = 'credit';
const TYPE_DEBIT = 'debit';
use TimestampableTrait;
/**
* The ID of the payment
*
* @var integer
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
protected $id;
/**
* the User object
*
* @var User
*
* @ORM\ManyToOne(targetEntity="User", inversedBy="payments")
* @ORM\JoinColumn(name="user_id", referencedColumnName="id", onDelete="CASCADE", nullable=false)
*/
protected $user;
/**
* payment type
*
* either 'credit' - a credit to the user's account
* or 'debit' - money taken out their account
*
* @var string
*
* @ORM\Column(name="payment_type", type="string", length=7, nullable=false)
*
* @Assert\Choice(choices= {"credit", "debit"}, message="Choose a valid payment type")
*/
protected $paymentType;
/**
* amount
*
* amount of payment, in pence
*
* @var int
*
* @ORM\Column(name="amount", type="integer", nullable=false)
*
* @Assert\Range(
* min = 1,
* max = 2000,
* minMessage = "Payments must be positive",
* maxMessage = "You cannot credit/debit more than £20"
* )
*/
protected $amount;
/**
* a string describing the transaction
*
* @var string
*
* @ORM\Column(name="description", type="string", length=255, nullable=false)
*
* @Assert\NotBlank(message="Please enter a description")
*/
protected $description;
....
我们在一个控制器中有如下代码:
public function creditUserAction(Request $request)
{
$body = $request->getContent();
$formData = json_decode($body, true);
$payment = new Payment();
$form = $this->createForm(new PaymentType(), $payment);
$form->submit($data);
if ($form->isValid()) {
// persist and flush .....
} ....
问题是,当createForm加载PaymentType表单时,Doctrine试图从数据库加载所有用户,并且有成千上万的用户
因此,我的问题是-有没有更好的方法来创建一个实体,使用Ajax POST请求,该实体与另一个使用Symfony表单的实体相关,其中相关实体有数千个实例?您可以在不创建表单的情况下验证您的实体
$validator = $this->get('validator');
$errors = $validator->validate($payment);
if(count($errors)) {
//...
}
同意。我希望使用Symfony表单也可以避免手动设置实体的每个属性——但是,手动设置每个属性并不是一项繁重的任务。谢谢你的帮助,我会用你建议的方法。