如何从gulpfile.js调用typescript方法
我有一个项目,我的如何从gulpfile.js调用typescript方法,typescript,gulp,Typescript,Gulp,我有一个项目,我的gulpfile.js相当复杂,因此我想将一些代码分解成typescript 如何从gulpfile.js调用typescript代码?从一开始可能更容易理解,但我就是这样争论的: config.ts export function getString() : string { return "getString() worked!"; } class Animal{ legs : number = 4; Sound():string{return
gulpfile.js
相当复杂,因此我想将一些代码分解成typescript
如何从gulpfile.js调用typescript代码?从一开始可能更容易理解,但我就是这样争论的: config.ts
export function getString() : string
{
return "getString() worked!";
}
class Animal{
legs : number = 4;
Sound():string{return "Woof!"}
}
export var dog = new Animal();
var gulp = require('gulp')
var config = require("./src/config.js");
gulp.task('default', function () {
console.log(config.getString());
console.log(config.dog.Sound());
console.log(config.dog.legs);
});
tsconfig.json
{
"include": [
"./src/**/*.ts"
],
"exclude": [
"node_modules",
"**/*.spec.ts"
],
"compilerOptions": {
"noImplicitAny": true,
"target": "es5",
"module": "commonjs",
"outDir" :"./src",
}
}
gulpfile.js
export function getString() : string
{
return "getString() worked!";
}
class Animal{
legs : number = 4;
Sound():string{return "Woof!"}
}
export var dog = new Animal();
var gulp = require('gulp')
var config = require("./src/config.js");
gulp.task('default', function () {
console.log(config.getString());
console.log(config.dog.Sound());
console.log(config.dog.legs);
});
输出
[21:03:43] Starting 'default'...
getString() worked!
Woof!
4
注释
export function getString() : string
{
return "getString() worked!";
}
class Animal{
legs : number = 4;
Sound():string{return "Woof!"}
}
export var dog = new Animal();
var gulp = require('gulp')
var config = require("./src/config.js");
gulp.task('default', function () {
console.log(config.getString());
console.log(config.dog.Sound());
console.log(config.dog.legs);
});
模块设置是关键commonjs
- gulp文件正在编译*.ts(此处未显示),这意味着当前gulp总是加载一个太旧的tsc版本。也许使用transfile语法会更好