Unix 如何用其他文件的内容替换文件中的字符串

我使用

ksh

在

AIX

上，我需要一些帮助，因为我无法通过

sed

或

awk

实现 模板文件：（作为输入）

...  
varchar SelectStmt = 'REPLACE_SELECT_STATEMENT'
...

---

上述中应应用的值（基于Teradata中表名的输入，分别比较每列的列数据类型，并在必要时强制转换）通过awk实现，并重新定向到一个文件，该文件有多行（>=100和模板文件

$ cat temp 
...  
varchar SelectStmt = 'REPLACE_SELECT_STATEMENT'
...

内容

$ cat output 
SELECT COLUMN1, CAST(COLUMN2 AS DECIMAL(10,3)),
       CAST(COLUMN3 AS VARCHAR(40)), COLUMN4,
       ....
       CAST(COLUMN600 AS INTEGER) 
FROM DATABASE1.TABLE1 WHERE COLUMN_DATE = '2017-01-31';

Awk

假设输出文件不包含将被解释的

&

通过更换操作

可读性更好的版本

SELECT COLUMN1, CAST(COLUMN2 AS DECIMAL(10,3)),
       CAST(COLUMN3 AS VARCHAR(40)), COLUMN4,
       ....
       CAST(COLUMN600 AS INTEGER) 
FROM DATABASE1.TABLE1 WHERE COLUMN_DATE = '2017-01-31';

awk '  # Here read output file and save contents in variable r
       NR==FNR{
            r=(FNR>1?r RS:"") $0
            next
        }

        # Here read file temp
        {
           gsub(/REPLACE_SELECT_STATEMENT/,r)
        }1
   ' output temp 

awk 'BEGIN{
        search="REPLACE_SELECT_STATEMENT"
}
NR==FNR{
        r=(FNR>1?r RS:"") $0
        next
} 
# To take care of & char, credit : Ed Morton
s=index($0,search){ 
        $0 = substr($0,1,s-1) r substr($0,s+length(search)) 
}1' output temp

如果输出文件中包含

&

字符

可读性更好的版本

SELECT COLUMN1, CAST(COLUMN2 AS DECIMAL(10,3)),
       CAST(COLUMN3 AS VARCHAR(40)), COLUMN4,
       ....
       CAST(COLUMN600 AS INTEGER) 
FROM DATABASE1.TABLE1 WHERE COLUMN_DATE = '2017-01-31';

awk '  # Here read output file and save contents in variable r
       NR==FNR{
            r=(FNR>1?r RS:"") $0
            next
        }

        # Here read file temp
        {
           gsub(/REPLACE_SELECT_STATEMENT/,r)
        }1
   ' output temp 

awk 'BEGIN{
        search="REPLACE_SELECT_STATEMENT"
}
NR==FNR{
        r=(FNR>1?r RS:"") $0
        next
} 
# To take care of & char, credit : Ed Morton
s=index($0,search){ 
        $0 = substr($0,1,s-1) r substr($0,s+length(search)) 
}1' output temp

两者都提供输出

...  
    varchar SelectStmt = 'SELECT COLUMN1, CAST(COLUMN2 AS DECIMAL(10,3)),
           CAST(COLUMN3 AS VARCHAR(40)), COLUMN4,
           ....
           CAST(COLUMN600 AS INTEGER) 
    FROM DATABASE1.TABLE1 WHERE COLUMN_DATE = '2017-01-31';'
 ...

...  
    varchar SelectStmt = 'SELECT COLUMN1, CAST(COLUMN2 AS DECIMAL(10,3)),
           CAST(COLUMN3 AS VARCHAR(40)), COLUMN4,
           ....
           CAST(COLUMN600 AS INTEGER) 
    FROM DATABASE1.TABLE1 WHERE COLUMN_DATE = '2017-01-31';'
...

Perl

$ perl -pe 's/REPLACE_SELECT_STATEMENT/`cat output`/ge' temp
...  
varchar SelectStmt = 'SELECT COLUMN1, CAST(COLUMN2 AS DECIMAL(10,3)),
       CAST(COLUMN3 AS VARCHAR(40)), COLUMN4,
       ....
       CAST(COLUMN600 AS INTEGER) 
FROM DATABASE1.TABLE1 WHERE COLUMN_DATE = '2017-01-31';
'
...

---

非常好，谢谢你，阿克谢·赫格德。

$ perl -pe 's/REPLACE_SELECT_STATEMENT/`cat output`/ge' temp
...  
varchar SelectStmt = 'SELECT COLUMN1, CAST(COLUMN2 AS DECIMAL(10,3)),
       CAST(COLUMN3 AS VARCHAR(40)), COLUMN4,
       ....
       CAST(COLUMN600 AS INTEGER) 
FROM DATABASE1.TABLE1 WHERE COLUMN_DATE = '2017-01-31';
'
...