Validation Symfony-如何根据另一个节点值验证配置节点?
在我的Configuration.php中,我的结构如下:Validation Symfony-如何根据另一个节点值验证配置节点?,validation,symfony,configuration,traits,Validation,Symfony,Configuration,Traits,在我的Configuration.php中,我的结构如下: public function getConfigTreeBuilder() { $treeBuilder = new TreeBuilder(); $rootNode = $treeBuilder->root('my_bundle'); $rootNode ->children() ->scalarNode('class')->cannotBeEmpty()->end()
public function getConfigTreeBuilder()
{
$treeBuilder = new TreeBuilder();
$rootNode = $treeBuilder->root('my_bundle');
$rootNode
->children()
->scalarNode('class')->cannotBeEmpty()->end()
->arrayNode('social_network')
->children()
->arrayNode('facebook')
->validate()
->ifTrue(function($node) {
// my logic to validate if the 'class' specified implements my trait
})
->thenInvalid('You must use XXXXXX trait in your class.')
->end()
->children()
->scalarNode('app_id')->isRequired()->cannotBeEmpty()->end()
->scalarNode('secret')->isRequired()->cannotBeEmpty()->end()
->end()
->end()
->end()
->end()
->end();
return $treeBuilder;
}
我需要检查指定的类是否实现了包中的特定trait部分
如何读取
函数($node)
中的类的值?这是一个有趣的问题,因此我决定进行实验,看看如何实现。通常,人们只会进行更一般的验证,这就是为什么我想您不能直接在getConfigTreeBuilder
函数中进行验证的原因。或者至少我找不到办法。您可以尝试执行函数($node)使用($rootNode)
,但无法获取节点的值。因此,即使尝试在匿名函数的范围内执行$rootNode->getNode('class')
,也无法获得实际值
另一方面,您可以做的是转到扩展
类(位于DependencyInjection
目录中)并在那里进行验证。像这样的东西应该能起作用:
public function load(array $configs, ContainerBuilder $container)
{
$configuration = new Configuration();
$config = $this->processConfiguration($configuration, $configs);
$class = $config['class'];
// Apply your logic here...
if(!$this->checkForTrait($class, 'myTrait')) {
throw new \ErrorException("The class ".$class." should implement myTrait!");
}
$loader = new Loader\YamlFileLoader($container, new FileLocator(__DIR__.'/../Resources/config'));
$loader->load('services.yml');
}
private function checkForTrait($class, $trait)
{
$class = new \ReflectionClass($class);
$traits = $class->getTraitNames(); // returns an array of all trait names being currently used in that class.
return in_array($trait, $traits);
}
我不知道这是否被视为“最佳实践”,所以如果有人有更好的解决方案,请指出:)您所要做的就是在scalarNode('class')
节点内调用validate()
方法。看一看:
public function getConfigTreeBuilder()
{
$treeBuilder = new TreeBuilder();
$rootNode = $treeBuilder->root('my_bundle');
$rootNode
->children()
->scalarNode('class')
->cannotBeEmpty()
->validate()
->ifTrue(function ($value) {
// my logic to validate if the 'class' specified implements my trait
$reflection = new \ReflectionClass($value);
$traitsNames = $reflection->getTraitNames();
return false === \in_array('myTrait', $traitsNames, true);
})
->thenInvalid('You must use XXXXXX trait in your class.')
->end()
->end()
->arrayNode('social_network')
->children()
->arrayNode('facebook')
->children()
->scalarNode('app_id')->isRequired()->cannotBeEmpty()->end()
->scalarNode('secret')->isRequired()->cannotBeEmpty()->end()
->end()
->end()
->end()
->end()
->end()
;
return $treeBuilder;
}
通过这种方式,验证是按照标量类
节点进行的。$value
是class
节点的值,因此它是类的名称
其余的:
$reflection = new \ReflectionClass($value);
$traitsNames = $reflection->getTraitNames();
return false === \in_array('myTrait', $traitsNames, true);
它只是一段php代码,用于验证是否实现了该特性