Web scraping 获得；属性错误：'；非类型'；对象没有属性'；获取'&引用；从flipkart中抓取数据时？

我正在尝试从Flipkart中替换移动数据。下面是我编写的代码

下面是图像的实际代码：

home_page_link = "https://www.flipkart.com"
href = "/search?q=mobiles&as=on&as- show=on&otracker=AS_Query_TrendingAutoSuggest_1_0_na_na_na&otracker1=AS_Query_TrendingAutoSuggest_1_0_na_na_na&as-pos=1&as-type=TRENDING&suggestionId=mobiles&requestId=55feeb8d-8549-48a8-9325-1c0e8756151e&page=1"
url = home_page_link + href
for i in range(1, 101):
    print("page: ", i)

    page_response = requests.get(url)
    print(page_response)
    soup = BeautifulSoup(page_response.content, 'html.parser')

#   cards = soup.find_all('div', attrs={'class': '_1UoZlX'})

#   for card in cards:
#       name = card.find("div", attrs={'class': '_3wU53n'})
#       price = card.find('div', attrs={'class': '_1vC4OE'})
#       print(name.text, price.text)
    

    next_link = soup.find("a",text = "Next")

    print(type(next_link))

    link = next_link.get("href")
    home_page_link = "https://www.flipkart.com"
    next_page_link = home_page_link + link
    url = next_page_link

我在第29页得到了非类型对象：

再次执行相同代码后：

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您试图在flipkart中更改页面以获取所有记录

通过更改链接中的最后一个字符，可以轻松更改页面。您只需更改链接中的页面值

要获取整个页面的所有内容，请尝试以下操作：

import requests
from bs4 import BeautifulSoup
home_page_link = "https://www.flipkart.com"
href = "/search?q=mobiles&as=on&as- show=on&otracker=AS_Query_TrendingAutoSuggest_1_0_na_na_na&otracker1=AS_Query_TrendingAutoSuggest_1_0_na_na_na&as-pos=1&as-type=TRENDING&suggestionId=mobiles&requestId=55feeb8d-8549-48a8-9325-1c0e8756151e&page="       # remove last character which show page number.
url = home_page_link + href
print(url)
for i in range(1, 101):
    print("page: ", i)
    new_url = url + str(i)       # add page number in the link every time value of `i` change, also page is increment.
    page_response = requests.get(new_url)
    print(page_response)
    soup = BeautifulSoup(page_response.content, 'html.parser')

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伟大的它起作用了。谢谢@Bhargav Desai。但是你能帮我理解为什么（text=“Next”）这个东西不起作用，即我的方法吗？即使这样，也可以获得下一页链接。我的代码面临的问题是什么？