WPF弹出窗口中的子菜单项
我已经在XAML的弹出窗口中创建了菜单项。该菜单项包含子菜单项。单击切换按钮时弹出窗口打开。我无法打开弹出菜单中菜单项的子菜单项 $WPF弹出窗口中的子菜单项,wpf,wpf-controls,Wpf,Wpf Controls,我已经在XAML的弹出窗口中创建了菜单项。该菜单项包含子菜单项。单击切换按钮时弹出窗口打开。我无法打开弹出菜单中菜单项的子菜单项 $ 请帮我解决这个问题。将菜单项包装在菜单中,它就会工作 <ToggleButton Name="button" Width="30" Height="30" Click="Button_Click"> <Image Wid
请帮我解决这个问题。将
菜单项
包装在菜单中,它就会工作
<ToggleButton Name="button"
Width="30"
Height="30"
Click="Button_Click">
<Image Width="30" Height="30">
<Image.Source>
<BitmapImage UriSource="/WpfApplication4;component/Images/Filter.png" />
</Image.Source>
</Image>
</ToggleButton>
<Popup Name="PART_Popup"
Placement="Bottom"
PlacementTarget="{Binding ElementName=button}">
<Border Background="White"
BorderBrush="Gray"
BorderThickness="1">
<StackPanel Orientation="Vertical">
<MenuItem Width="270"
Margin="5"
Header="ClearFilter">
<MenuItem.Icon>
<Image>
<Image.Source>
<BitmapImage UriSource="/WpfApplication4;component/Images/ClearFilter.png" />
</Image.Source>
</Image>
</MenuItem.Icon>
<MenuItem Header="SubMenu" />
<MenuItem Header="SubMenu1" />
</MenuItem>
</StackPanel>
</Border>
</Popup>