XSLT 1.0:键在选择节点时不起作用
我有一个提供当前输出的XML和XSLT。它使用一个“键”,但我没有得到预期的输出 源XML:XSLT 1.0:键在选择节点时不起作用,xslt,key,xslt-1.0,Xslt,Key,Xslt 1.0,我有一个提供当前输出的XML和XSLT。它使用一个“键”,但我没有得到预期的输出 源XML: <?xml version="1.0" encoding="UTF-8"?> <Root> <Receivers> <ReceiverRule> <Condition> <Value>Condition 1<
<?xml version="1.0" encoding="UTF-8"?>
<Root>
<Receivers>
<ReceiverRule>
<Condition>
<Value>Condition 1</Value>
</Condition>
<Receiver>
<party>party1</party>
<system>SYS1</system>
</Receiver>
</ReceiverRule>
<ReceiverRule>
<Condition>
<Value>Condition 2</Value>
</Condition>
<Receiver>
<party>party2</party>
<system>SYS2</system>
</Receiver>
</ReceiverRule>
</Receivers>
<ReceiverInterfaces>
<Receiver>
<party>party1</party>
<system>SYS1</system>
</Receiver>
<ReceiverInterfaceRule>
<Rule>Rule 1 sytem 1</Rule>
</ReceiverInterfaceRule>
<ReceiverInterfaceRule>
<Rule>Rule 2 system 1</Rule>
</ReceiverInterfaceRule>
</ReceiverInterfaces>
<ReceiverInterfaces>
<Receiver>
<party>party2</party>
<system>SYS2</system>
</Receiver>
<ReceiverInterfaceRule>
<Rule>Rule 1 system 2</Rule>
</ReceiverInterfaceRule>
<ReceiverInterfaceRule>
<Rule>Rule 2 system 2</Rule>
</ReceiverInterfaceRule>
</ReceiverInterfaces>
</Root>
条件1
第1方
系统1
条件2
第2部分
系统2
第1方
系统1
规则1系统1
规则2制度1
第2部分
系统2
规则1制度2
规则2系统2
我的XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output indent="yes"/>
<xsl:key name="Receiver" match="ReceiverRule/Receiver" use="concat(party,system)"/>
<xsl:template match="Root">
<ReceiverList>
<xsl:apply-templates select="Receivers/ReceiverRule"/>
</ReceiverList>
</xsl:template>
<xsl:template match="ReceiverRule">
<Receiver>
<Name>
<xsl:value-of select="concat(Receiver/party, ' ' ,Receiver/system)"/>
</Name>
<Condition>
<xsl:value-of select="Condition/Value"/>
</Condition>
<xsl:apply-templates select="ancestor::Root/ReceiverInterfaces
[Receiver/child::* = key('Receiver',Root/Receivers/ReceiverRule/Receiver)]"/>
</Receiver>
</xsl:template>
<xsl:template match="ReceiverInterfaces">
<xsl:apply-templates select="ReceiverInterfaceRule"/>
</xsl:template>
<xsl:template match="ReceiverInterfaceRule">
<Rule>
<xsl:value-of select="Rule"/>
</Rule>
</xsl:template>
</xsl:stylesheet>
生成此XML输出:
<?xml version="1.0" encoding="UTF-8"?>
<ReceiverList>
<Receiver>
<Name>party1 SYS1</Name>
<Condition>Condition 1</Condition>
</Receiver>
<Receiver>
<Name>party2 SYS2</Name>
<Condition>Condition 2</Condition>
</Receiver>
</ReceiverList>
第1部分系统1
条件1
第2部分系统2
条件2
但我期待这一结果:
<?xml version="1.0" encoding="UTF-8"?>
<ReceiverList>
<Receiver>
<Name>party1 SYS1</Name>
<Condition>Condition 1</Condition>
<Rule>Rule 1 sytem 1</Rule>
<Rule>Rule 2 system 1</Rule>
</Receiver>
<Receiver>
<Name>party2 SYS2</Name>
<Condition>Condition 2</Condition>
<Rule>Rule 1 system 2</Rule>
<Rule>Rule 2 system 2</Rule>
</Receiver>
</ReceiverList>
第1部分系统1
条件1
规则1系统1
规则2制度1
第2部分系统2
条件2
规则1制度2
规则2系统2
不知怎的,我的钥匙不认识。我很感激任何关于我做错了什么的暗示。
非常感谢。
彼得我认为他不是
<xsl:apply-templates select="ancestor::Root/ReceiverInterfaces
[Receiver/child::* = key('Receiver',Root/Receivers/ReceiverRule/Receiver)]"/>
你想要的只是
<xsl:apply-templates select="key('Receiver', concat(Receiver/party, Receiver/system))/ReceiverInterfaceRule"/>
用钥匙
<xsl:key name="Receiver" match="ReceiverInterfaces" use="concat(Receiver/party, Receiver/system)"/>
Martin,谢谢!我很挣扎,但在你的“编辑”后,它工作正常。说到“钥匙”,我总是迷路。你的个人资料令人印象深刻!向你问好,彼得