.net 使用F更改XML序列化中的标记名#

这就是我得到的：

<Recipients>
    <recipients>
             <mid_name /> 
             <last_name>Community</last_name> 
             <company>co, inc.</company> 
             <user_id>871</user_id> 
             <email>community@co.com</email> 
     </recipients>
</Recipients>

社区
公司。
871
community@co.com 

应该是这样的

<recipients>
    <recipient>
             <mid_name /> 
             <last_name>Community</last_name> 
             <company>co, inc.</company> 
             <user_id>871</user_id> 
             <email>community@co.com</email> 
     </recipient>
</recipients>

社区
公司。
871
community@co.com 

这就是我的数据模型的样子：

type recipient(userId:int,  first:string, last:string, email: string, company: string) = 
    let mutable first = first
    let mutable mid = "" ;
    let mutable last = last
    let mutable company = company
    let mutable userId = userId
    let mutable email = email

    public new() =
        new recipient(12180,"Joe","Plumber","Joe@plumber.com","tubes tied, inc")

    [<XmlElement("first_name")>] 
    member this.First with get() = first and set v = first <- v

    [<XmlElement("mid_name")>] 
    member this.Mid with get() = mid and set v = mid <- v

    [<XmlElement("last_name")>] 
    member this.Last with get() = last and set v = last <- v

    [<XmlElement("company")>] 
    member this.Company with get() = company and set v = company <- v

    [<XmlElement("user_id")>] 
    member this.UserId with get() = userId and set v = userId <- v

    [<XmlElement("email")>] 
    member this.Email with get() = email and set v = email <- v

键入收件人（userId:int，first:string，last:string，email:string，company:string）=
设mutable first=first
让可变中间=”；
让可变的last=last
让可变公司=公司
让可变userId=userId
让可变电子邮件=电子邮件
公共新=
新接受者（12180，“乔”，“管道工”Joe@plumber.com“，“管系公司”）
[] 
使用get（）=First和set v=First来成员this.First我认为应该使用

[<XmlElement "recipients">]

[]

现在看起来您正在用数组属性装饰数组
此外，您可以将ElementName=“recipients”设置为“recipient”

这是一个更完整的示例，我考虑了其他属性：

type recipient (f:string) = 
   let mutable first = f

   public new () = recipient ("")                   

   [<System.Xml.Serialization.XmlElement("first_name")>] 
   member this.First with get() = first and set v = first <- v



   [<System.Xml.Serialization.XmlRoot("recipients")>]
   type Record (recepts: recipient array) =

      let mutable recipients = recepts

      public new () = Record(Array.empty)                 

      [<System.Xml.Serialization.XmlElement("recipient")>]
      member this.Recipients with get() = recipients and set v = recipients <- v   

类型收件人（f:string）=
设可变优先=f
public new（）=收件人（“”）
[] 
使用get（）=First和set v=First来成员this.First我认为应该使用

[<XmlElement "recipients">]

[]

现在看起来您正在用数组属性装饰数组
此外，您可以将ElementName=“recipients”设置为“recipient”

这是一个更完整的示例，我考虑了其他属性：

type recipient (f:string) = 
   let mutable first = f

   public new () = recipient ("")                   

   [<System.Xml.Serialization.XmlElement("first_name")>] 
   member this.First with get() = first and set v = first <- v



   [<System.Xml.Serialization.XmlRoot("recipients")>]
   type Record (recepts: recipient array) =

      let mutable recipients = recepts

      public new () = Record(Array.empty)                 

      [<System.Xml.Serialization.XmlElement("recipient")>]
      member this.Recipients with get() = recipients and set v = recipients <- v   

类型收件人（f:string）=
设可变优先=f
public new（）=收件人（“”）
[] 
请记住这一点。首先，使用get（）=First和set v=FirstAlex非常接近，您需要的魔法juju是将
[]
放在非常接近的位置，您需要的魔法jujuju是将
[]
放在非常接近的位置。在记录类型中，存在类型为recipient.yes的收件人数组。在记录类型中，存在类型为recipient的收件人数组。
<recipients xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<recipient>
    <first_name>a</first_name>
</recipient>
<recipient>
    <first_name>b</first_name>
</recipient>
<recipient>
    <first_name>c</first_name>
</recipient>