Ajax 创建动态导航子菜单使用Codeigniter从数据库中选择？

我正在尝试使用ajax在codeigniter中创建一个带有子菜单的菜单。我成功地创建了菜单，但在创建子菜单时遇到了问题。当我点击菜单时，我在cosole.log中检查它，它显示的控制器是获取详细信息，但之后我不知道为什么它不工作。请任何人解决这个问题。提前谢谢 这是我的视野范围

<form action="" method="post" id="frm_submenu">
               <div class="form-group">
               <label for="menu">Select Menu</label>
                   <select class="form-control" id="selectmenuid">
                    <option value="">-- Select Menu --</option>
                    <?php foreach($showData as $show):?>
                      <option value="<?php echo $show->menu_id?>"><?php echo $show->menu_name?></option>
                    <?php endforeach;?>
                    </select>
                </div>
               <div class="form-group">
               <label for="menu">Select Sub Menu</label>
                   <select class="form-control" id="selectsubmenu">
                    <option value="">-- Select Submenu Menu --</option>
                    </select>
               </div>
              <div class="form-group">
                  <label for="imagetitle">Image Title</label>
                  <input type="text" class="form-control" name="imagetitle" id="imagetitle" placeholder="Enter Image Title" required="required">
                </div>
              <div class="form-group">
              <label class="btn btn-default btn-file">
                Browse <input type="file" style="display: none;">
              </label>
              </div>
               <button type="submit" class="btn btn-primary" id="submit">Submit</button>
           </form>

这是我的示范区

public function getSubmenu(){  
    $this->db->select('submenu_id,submenu_name');
     $this->db->from('menu,submenu');
     $this->db->where('submenu.menu_id=menu.menu_id');
     $this->db->where('submenu.menu_id', $selectmenuid);
      return $query->result_array();    
 }

---

您必须在模型方法中接收

$selectmenuid

：

public function getSubmenu($selectmenuid){  
    $this->db->select('submenu_id,submenu_name');
    $this->db->from('menu,submenu');
    $this->db->where('submenu.menu_id=menu.menu_id');
    $this->db->where('submenu.menu_id', $selectmenuid);
    return $query->result_array();    
}

public function getSubmenu(){  
    $this->db->select('submenu_id,submenu_name');
     $this->db->from('menu,submenu');
     $this->db->where('submenu.menu_id=menu.menu_id');
     $this->db->where('submenu.menu_id', $selectmenuid);
      return $query->result_array();    
 }

public function getSubmenu($selectmenuid){  
    $this->db->select('submenu_id,submenu_name');
    $this->db->from('menu,submenu');
    $this->db->where('submenu.menu_id=menu.menu_id');
    $this->db->where('submenu.menu_id', $selectmenuid);
    return $query->result_array();    
}