Android 对于xml drawable中定义的形状,BitmapFactory.decodeResource()返回null
我浏览了许多类似的问题,尽管我还没有找到我的问题的正确答案 我有一个可绘制的,在shape.xml中定义的Android 对于xml drawable中定义的形状,BitmapFactory.decodeResource()返回null,android,android-drawable,xml-drawable,Android,Android Drawable,Xml Drawable,我浏览了许多类似的问题,尽管我还没有找到我的问题的正确答案 我有一个可绘制的,在shape.xml中定义的 <?xml version="1.0" encoding="utf-8"?> <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle" > <so
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle" >
<solid android:color="@color/bg_color" />
</shape>
我做错了什么?
BitmapFactory.decodeResource()
是否适用于xml定义的可绘制文件?由于您希望加载的是可绘制文件而不是位图,请使用以下方法:
Drawable d = getResources().getDrawable(R.drawable.your_drawable, your_app_theme);
要将其转换为位图
:
public static Bitmap drawableToBitmap (Drawable drawable) {
if (drawable instanceof BitmapDrawable) {
return ((BitmapDrawable)drawable).getBitmap();
}
Bitmap bitmap = Bitmap.createBitmap(drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
摘自:它是可绘制的,不是位图。您应该使用
getDrawable
来代替您可能已经将.xml
放入目录:…/drawable-24
,并尝试将其放入…/drawable
中
public static Bitmap convertDrawableResToBitmap(@DrawableRes int drawableId, Integer width, Integer height) {
Drawable d = getResources().getDrawable(drawableId);
if (d instanceof BitmapDrawable) {
return ((BitmapDrawable) d).getBitmap();
}
if (d instanceof GradientDrawable) {
GradientDrawable g = (GradientDrawable) d;
int w = d.getIntrinsicWidth() > 0 ? d.getIntrinsicWidth() : width;
int h = d.getIntrinsicHeight() > 0 ? d.getIntrinsicHeight() : height;
Bitmap bitmap = Bitmap.createBitmap(w, h, Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
g.setBounds(0, 0, w, h);
g.setStroke(1, Color.BLACK);
g.setFilterBitmap(true);
g.draw(canvas);
return bitmap;
}
Bitmap bit = BitmapFactory.decodeResource(getResources(), drawableId);
return bit.copy(Bitmap.Config.ARGB_8888, true);
}
//------------------------
Bitmap b = convertDrawableResToBitmap(R.drawable.myDraw , 50, 50);
它对我有用,希望这能帮助别人。我想知道这是怎么回事。。。由于可绘制图形是在XML中定义的形状,
getIntrinsicWidth()
和getIntrinsicHeight()
将始终返回-1,并且不会创建位图。或者我搞错了什么?这会抛出IllegalArgumentException:width和height必须>0
,这意味着您的可绘制文件没有有效的大小。使用新的支持库更新:使用ContextCompat.GetDrawable(context,id)Drawable类的Koltin扩展:您不能在StateListDrawable或Shapead上使用getDrawable
,并对您的答案进行解释
public static Bitmap convertDrawableResToBitmap(@DrawableRes int drawableId, Integer width, Integer height) {
Drawable d = getResources().getDrawable(drawableId);
if (d instanceof BitmapDrawable) {
return ((BitmapDrawable) d).getBitmap();
}
if (d instanceof GradientDrawable) {
GradientDrawable g = (GradientDrawable) d;
int w = d.getIntrinsicWidth() > 0 ? d.getIntrinsicWidth() : width;
int h = d.getIntrinsicHeight() > 0 ? d.getIntrinsicHeight() : height;
Bitmap bitmap = Bitmap.createBitmap(w, h, Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
g.setBounds(0, 0, w, h);
g.setStroke(1, Color.BLACK);
g.setFilterBitmap(true);
g.draw(canvas);
return bitmap;
}
Bitmap bit = BitmapFactory.decodeResource(getResources(), drawableId);
return bit.copy(Bitmap.Config.ARGB_8888, true);
}
//------------------------
Bitmap b = convertDrawableResToBitmap(R.drawable.myDraw , 50, 50);