Android:XML解析问题

我可以使用以下方法在此文件中读取和显示xml

private void loadTopMoversData() {
    ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();
    try {
        String xml = XMLfunctions.getXML(TOPMOVERS_XML);
        Document doc = XMLfunctions.XMLfromString(xml);
        NodeList nodes = doc.getElementsByTagName("scrip");

        for (int i = 0; i < nodes.getLength(); i++) {       
            HashMap<String, String> map = new HashMap<String, String>();    

            Element e = (Element)nodes.item(i);
            map.put("name", XMLfunctions.getValue(e, "name"));
            map.put("currprice", XMLfunctions.getValue(e, "currprice"));
            map.put("percentage", XMLfunctions.getValue(e, "percentage"));
            map.put("code", XMLfunctions.getValue(e, "code"));
            mylist.add(map);

            Log.i("tag", XMLfunctions.getValue(e, "headline") + " " + XMLfunctions.getValue(e, "time") );
        }
    }

但是我无法使用相同的方法，但使用适当的标记来解析其中的xml。我做错了什么

private void loadNewsData() {
     ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();
    try {

        String xml = XMLfunctions.getXML(NEWS_XML);
        Document doc = XMLfunctions.XMLfromString(xml);
        NodeList nodes = doc.getElementsByTagName("data");
        ArrayList<String> links = new ArrayList<String>();
        for (int i = 0; i < nodes.getLength(); i++) {   
            Element e = (Element)nodes.item(i);

            HashMap<String, String> map = new HashMap<String, String>();    
            map.put("headline", XMLfunctions.getValue(e, "headline"));
            map.put("link", XMLfunctions.getValue(e, "link"));
            map.put("time", XMLfunctions.getValue(e, "time"));
            links.add(XMLfunctions.getValue(e, "link"));
            mylist.add(map);            

            Log.i("tag", XMLfunctions.getValue(e, "headline") + " " + XMLfunctions.getValue(e, "time") );
        }   

    } catch (Exception e) {
        Log.e("tag", e.getMessage());
    }   
}`

这是我的XmlFunctions.java

public class XMLfunctions {

public final static Document XMLfromString(String xml){

    Document doc = null;

    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    try {

        DocumentBuilder db = dbf.newDocumentBuilder();

        InputSource is = new InputSource();
        is.setCharacterStream(new StringReader(xml));
        doc = db.parse(is); 

    } catch (ParserConfigurationException e) {
        System.out.println("XML parse error: " + e.getMessage());
        return null;
    } catch (SAXException e) {
        System.out.println("Wrong XML file structure: " + e.getMessage());
        return null;
    } catch (IOException e) {
        System.out.println("I/O exeption: " + e.getMessage());
        return null;
    }

    return doc;

}

 public final static String getElementValue( Node elem ) {
     Node kid;
     if( elem != null){
         if (elem.hasChildNodes()){
             for( kid = elem.getFirstChild(); kid != null; kid = kid.getNextSibling() ){
                 if( kid.getNodeType() == Node.TEXT_NODE  ){
                     return kid.getNodeValue();
                 }
             }
         }
     }
     return "";
 }

 public static String getXML(String webURL){     
        String line = null;

        try {

            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(webURL);

            HttpResponse httpResponse = httpClient.execute(httpPost);
            HttpEntity httpEntity = httpResponse.getEntity();
            line = EntityUtils.toString(httpEntity);

        } catch (UnsupportedEncodingException e) {
            line = "<results status=\"error\"><msg>Can't connect to server</msg></results>";
        } catch (MalformedURLException e) {
            line = "<results status=\"error\"><msg>Can't connect to server</msg></results>";
        } catch (IOException e) {
            line = "<results status=\"error\"><msg>Can't connect to server</msg></results>";
        }

        return line;

}

public static int numResults(Document doc){     
    Node results = doc.getDocumentElement();
    int res = -1;

    try{
        res = Integer.valueOf(results.getAttributes().getNamedItem("count").getNodeValue());
    }catch(Exception e ){
        res = -1;
    }

    return res;
}

public static String getValue(Element item, String str) {       
    NodeList n = item.getElementsByTagName(str);        
    return XMLfunctions.getElementValue(n.item(0));
}
}

这与xml文件有关吗？请帮忙。谢谢

编辑：

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还有谁能告诉我如何使用此解析器解析包含“&”的XML吗？

您可能需要重新检查XML节点名称，区分大小写。还要检查您的链接数组是否正常工作

我解决了这个问题。在XMLfunctions.java中，它检查该节点是否是文本节点，并且xml中的节点显然不是文本节点

if( kid.getNodeType() == Node.TEXT_NODE  ){
                 return kid.getNodeValue();
}

---

所以，我删除了这个条件，现在它可以正常工作了。谢谢

第二个提要不是正确的XML。正如你所想&这不是正确的逃脱。它必须是这样的：&；见和

但是，一些解析器可以容忍这种情况，并且不会出错。你的解析器不是一个，如果这些

---

您可以尝试几个不同的解析器，也可以尝试在开始解析之前通过查找替换来修复提要。如果您这样做，您必须小心不要重新转义已转义的字符，否则您将得到如下结果：&；amp

解析第二个文档时会出现什么错误？我可以对解析XML的方式说eww吗？我可以建议您使用基于注释的解析器，如Simple。我甚至在这里写了一篇关于如何使用它的博客：