将图像从android发送到wamp服务器

我正在尝试将一个PNG图像从android设备发送到我笔记本电脑上运行的wamp服务器。以下是我用于AsyncTask的代码

public class UploadImage extends AsyncTask<Void, Void, Void> {
        Bitmap image;
        String name;
        ArrayList<NameValuePair> dataToSend = new ArrayList();
        Bitmap SendImg1;

        public UploadImage(String rc){

            int w,h;
            name = rc;

            try{
                SendImg1 = BitmapFactory.decodeFile(name);
                w = SendImg1.getHeight();
                Integer i = new Integer(w);
                String s = i.toString();
                Toast.makeText(getApplicationContext(), s,Toast.LENGTH_SHORT).show();
                Toast.makeText(getApplicationContext(), "rc is " + rc,Toast.LENGTH_SHORT).show();
                Toast.makeText(getApplicationContext(), "name is " + rc,Toast.LENGTH_SHORT).show();
            }

            catch(Exception e) {
                e.printStackTrace();
                Toast.makeText(getApplicationContext(), "Error in constructor",Toast.LENGTH_SHORT).show();
            }

            image = SendImg1;

        }

        @Override
        protected Void doInBackground(Void... arg0) {

            Toast.makeText(getApplicationContext(), "Inside OnPreEXEC" , Toast.LENGTH_SHORT).show();

            ByteArrayOutputStream baos = new ByteArrayOutputStream();
            image.compress(Bitmap.CompressFormat.PNG, 100, baos);
            String encodedImage = Base64.encodeToString(baos.toByteArray(), Base64.DEFAULT);
            dataToSend.add(new BasicNameValuePair("image", encodedImage));
            dataToSend.add(new BasicNameValuePair("name", name));
            HttpParams httpRequestParams = getHttpRequestParams();
            HttpClient client = new DefaultHttpClient(httpRequestParams);
            HttpPost post = new HttpPost(SERVERADDRESS + "/SavePicture.php");


            try{    
            post.setEntity(new UrlEncodedFormEntity(dataToSend));
            Toast.makeText(getApplicationContext(), "Inside try block of Onpostexec",Toast.LENGTH_SHORT).show();
            client.execute(post);
            Toast.makeText(getApplicationContext(), "Inside try block after client.execute(post) ",Toast.LENGTH_SHORT).show();
        }
        catch(Exception e)
        {
            e.printStackTrace();
            Toast.makeText(getApplicationContext(), "Problem in doinBG",Toast.LENGTH_SHORT).show();

        }


            return null; 
        }//doinBackground ends

        @Override
        protected void onPostExecute(Void result) {

            Toast.makeText(getApplicationContext(), "Inside onpost exec",Toast.LENGTH_SHORT).show();

            // TODO Auto-generated method stub
            // code from BG starts here



            // code from BG ends here



            Toast.makeText(getApplicationContext(), "Image sent to the server",Toast.LENGTH_SHORT).show();
            super.onPostExecute(result);
            //Toast.makeText(getApplicationContext(), "Image Uploaded" , Toast.LENGTH_SHORT).show();
        }

        @Override
        protected void onPreExecute() {


            super.onPreExecute();
        }

    }

---

他不来了。因此，我觉得我在这一行中可能出错了，但我无法确切地理解如何做？

这段代码对测试它的许多事情都有影响。我建议你去掉一些东西。首先发布一个简单的字符串，并检查后端是否接收到它。完成后，添加一个字符串作为伪图像，然后检查图像的编码逻辑是否正常工作。不能在异步任务的doInBackground（）中调用Toast（）。你的应用程序将立即崩溃。但你没有报告撞车！将它们更改为Log.d（）语句。在你这么做之后，这里的代码也改变了。明白了。。。问题是超时延迟…我只需要增加它。。。但是接收到一个零字节的空白图像。。可能出了什么问题

    client.execute(post);