Android 在房间数据库中插入值

Android 在房间数据库中插入值,android,android-room,Android,Android Room,我正在尝试使用按钮单击将数据插入数据库: 在我的main活动中,我正在使用: package com.example.trial; public CityViewModel mcityViewModel; @Override protected void onCreate(Bundle savedInstanceState) { ImageButton fab = findViewById(R.id.fab); fab.setOnClickListener(new V

我正在尝试使用按钮单击将数据插入数据库:

在我的main活动中,我正在使用:

 package com.example.trial;

 public CityViewModel  mcityViewModel;

  @Override
  protected void onCreate(Bundle savedInstanceState) {
 ImageButton fab = findViewById(R.id.fab);
    fab.setOnClickListener(new View.OnClickListener() {
      @Override
      public void onClick(View view) {
        String cityName = cityNameWeakReference.getText().toString();
        City cityItem = new City(cityName, 5.0,4.0);
        Snackbar.make(view, cityName+cityItem, Snackbar.LENGTH_LONG)
            .setAction("Action", null).show();
        mcityViewModel.insert(cityItem);
      }
    });
为了更容易地查看与数据库相关的代码,我在
com.example.trial.db
中定义了所有与数据库相关的文件(除了
DbActivity
,其中显示了
recyclerview

我的实体

package com.example.trial.db

Entity(tableName = "city_table")
public class City {

  @NonNull
  @PrimaryKey
  @ColumnInfo(name = "city")
  private String city = "Atlantis";

  @NonNull
  @ColumnInfo(name = "latitude")
  private Double latitude = 0.0;

  @NonNull
  @ColumnInfo(name = "Longitude")
  private Double longitude = 0.0;

  public City(@NonNull String city, @NonNull Double latitude, @NonNull Double longitude) {
    this.city = city;
    this.latitude = latitude;
    this.longitude = longitude;
  }

  ... getter and setter for city, latitude and longitude ...
  ... not showing for brevity. If you think that is necessary, please ask...
Dao

package com.example.trial.db

@Dao
public interface CityDao{

  @Insert(onConflict = OnConflictStrategy.IGNORE)
  void insert(City city);

  @Query("DELETE FROM city_table")
  void deleteAll();

  @Delete
  void deleteCity(City city);

  @Query("SELECT * from city_table LIMIT 1")
  City[] getAnyCity();

  @Query("SELECT * from city_table ORDER BY city ASC")
  LiveData<List<City>> getAllCity();
}
snackbar
给出了一些值,这表明,
cityItem
也不是空的,但我仍然得到了这个错误

我对java非常陌生,试图从
codelabs
构建它。但我无法找出我在这里做错了什么


请帮忙。

看起来您没有在
onCreate(Bundle savedInstanceState)
中初始化
mcityViewModel

请在
onCreate
方法中添加此行:

mcityViewModel=newviewmodelprovider(this.get)(CityViewModel.class)

@覆盖
创建时受保护的void(Bundle savedInstanceState){
//------>在此处添加此行
package com.example.trial.db

public class CityViewModel extends AndroidViewModel {
    private CityRepository mRepository;
    private LiveData<List<City>> mAllCity;

    public CityViewModel(Application application) {
        super(application);
        mRepository = new CityRepository(application);
        mAllCity = mRepository.getAllCity();
    }

    public LiveData<List<City>> getAllCity() {
        return mAllCity;
    }

    public void insert(City city) { mRepository.insert(city); }
    public void deleteCity(City city) { mRepository.deleteCity(city); }
    public void deleteAll() {
        mRepository.deleteAll();
    }

}
java.lang.NullPointerException: Attempt to invoke virtual method 'void com.example.trial.db.CityViewModel.insert(com.example.trial.db.City)' on a null object reference
@Override
protected void onCreate(Bundle savedInstanceState) {
    // -------> Add this line here <-------
    mcityViewModel = new ViewModelProvider(this).get(CityViewModel.class);

    ImageButton fab = findViewById(R.id.fab);
    fab.setOnClickListener(new View.OnClickListener() {
      @Override
      public void onClick(View view) {
        String cityName = cityNameWeakReference.getText().toString();
        City cityItem = new City(cityName, 5.0,4.0);
        Snackbar.make(view, cityName+cityItem, Snackbar.LENGTH_LONG)
            .setAction("Action", null).show();
        mcityViewModel.insert(cityItem);
      }
    });
}