Android 使用asynctask将图像发送到webservice
我有一个应用程序,可以拍摄一张照片,并提供给我一个给定图片的uri。 接下来,我要做的是将这张图片发送到我的Web服务 但是,一旦我尝试了这个方法,我就遇到了一个以前遇到过的错误,这与异步任务有关。因此,为了解决这个问题,我得到了一个HttpManager类,它保存了关于如何连接到web服务、url本身以及它在哪里处理图像uri的信息Android 使用asynctask将图像发送到webservice,android,image,web-services,android-asynctask,uri,Android,Image,Web Services,Android Asynctask,Uri,我有一个应用程序,可以拍摄一张照片,并提供给我一个给定图片的uri。 接下来,我要做的是将这张图片发送到我的Web服务 但是,一旦我尝试了这个方法,我就遇到了一个以前遇到过的错误,这与异步任务有关。因此,为了解决这个问题,我得到了一个HttpManager类,它保存了关于如何连接到web服务、url本身以及它在哪里处理图像uri的信息 public static String uploadImageToWebservice(String uri, String imageUri) { H
public static String uploadImageToWebservice(String uri, String imageUri) {
HttpURLConnection connection = null;
int responseCode = 0;
String image = "";
try {
URL url = new URL(uri + imageUri);
connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setInstanceFollowRedirects(false);
connection.setRequestMethod("GET");
connection.setRequestProperty("Content-Type", "text/plain");
/*
* String userpassword = adminUser + ":" + adminPassword; String
* encodedAuthorization = DatatypeConverter
* .printBase64Binary(userpassword.getBytes("UTF-8"));
* connection.setRequestProperty("Authorization", "Basic " +
* encodedAuthorization);
*/
InputStream is = connection.getInputStream();
image = is.toString();
responseCode = connection.getResponseCode();
connection.disconnect();
} catch (IOException e) {
Log.e("URL", "failure response from server >" + e.getMessage()
+ "<");
} finally {
if (connection != null) {
connection.disconnect();
}
}
return image;
}
publicstaticstringuploadImageTowerService(stringURI,stringImageURI){
HttpURLConnection=null;
int-responseCode=0;
字符串图像=”;
试一试{
URL=新URL(uri+imageUri);
connection=(HttpURLConnection)url.openConnection();
connection.setDoOutput(真);
connection.setInstanceFollowDirections(false);
connection.setRequestMethod(“GET”);
setRequestProperty(“内容类型”、“文本/普通”);
/*
*字符串userpassword=adminUser+:“+adminPassword;字符串
*encodedAuthorization=数据类型转换器
*.printBase64Binary(userpassword.getBytes(“UTF-8”);
*connection.setRequestProperty(“授权”、“基本”+
*编码(授权);
*/
InputStream is=connection.getInputStream();
image=is.toString();
responseCode=connection.getResponseCode();
连接断开();
}捕获(IOE异常){
Log.e(“URL”,“来自服务器的故障响应>”+e.getMessage()
+“使用代码上载图像
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
FileInputStream fileInputStream = new FileInputStream("sourcefile");
URL url = new URL("URL");
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type",
"multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("bill", sourceFileUri);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"bill\";filename=\""
+ sourceFileUri + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file
// data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
// String serverResponseMessage = conn
// .getResponseMessage();
if (serverResponseCode == 200) {
statud = "uploaded";
// messageText.setText(msg);
// Toast.makeText(ctx, "File Upload Complete.",
// Toast.LENGTH_SHORT).show();
// System.out.println("Uploaded successfyuly http: 200");
// recursiveDelete(mDirectory1);
}
// close the streams //
fileInputStream.close();
dos.flush();
dos.close();
php代码
<?php
$uploads_dir = './images/';
$tmp_name = $_FILES['bill']['tmp_name'];
$pic_name = $_FILES['bill']['name'];
if (move_uploaded_file($tmp_name, $uploads_dir.$pic_name )) {
echo "uploaded";
}
?>
这行不通,因为我正在使用android,所以我需要包含asynctask。否则,如果不使用它,我会出现异常。你必须在asynctask中的doinbackground方法中使用此代码。okI很快就会尝试此操作!有太多变量没有在你的代码@raj中说明-你能帮我解决吗?如果你需要上传图像到服务器端,首先使用Base64将其编码为字符串,然后在服务器端将其解码为图像。这将有助于减少android应用程序中的内存异常处理。
<?php
$uploads_dir = './images/';
$tmp_name = $_FILES['bill']['tmp_name'];
$pic_name = $_FILES['bill']['name'];
if (move_uploaded_file($tmp_name, $uploads_dir.$pic_name )) {
echo "uploaded";
}
?>