Android 带片段的反向导航WebView
我已经仔细研究了每一个与“后退”按钮在片段中使用WebView有关的问题,但在我的例子中,似乎无法使其正常工作 我目前正在尝试获取工作的答案,但我的应用程序只在按下后退按钮后关闭 任何帮助都会很好,谢谢Android 带片段的反向导航WebView,android,webview,android-webview,Android,Webview,Android Webview,我已经仔细研究了每一个与“后退”按钮在片段中使用WebView有关的问题,但在我的例子中,似乎无法使其正常工作 我目前正在尝试获取工作的答案,但我的应用程序只在按下后退按钮后关闭 任何帮助都会很好,谢谢 public class MainActivity extends BaseActivity { private Fragment FragmentArchietecture = new FragmentShakira(); WebView webview; private Fragmen
public class MainActivity extends BaseActivity {
private Fragment FragmentArchietecture = new FragmentShakira();
WebView webview;
private Fragment mContent;
public MainActivity() {
super(R.string.app_name);
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
if (savedInstanceState != null)
mContent = getSupportFragmentManager().getFragment(
savedInstanceState, "mContent");
if (mContent == null)
mContent = new FragmentShakira();
setContentView(R.layout.content_frame);
getSupportFragmentManager().beginTransaction()
.replace(R.id.content_frame, FragmentArchietecture, "webby")
.commit();
setBehindContentView(R.layout.menu_frame);
getSupportFragmentManager().beginTransaction()
.replace(R.id.menu_frame, new RandomList()).commit();
ActionBar bar = getSupportActionBar();
bar.setTitle(R.string.app_name);
getSlidingMenu().setTouchModeAbove(SlidingMenu.TOUCHMODE_FULLSCREEN);
setSlidingActionBarEnabled(true);
}
@Override
public void onBackPressed() {
Fragment webview = getSupportFragmentManager().findFragmentByTag(
"webby");
if (webview instanceof FragmentShakira) {
boolean goback = ((FragmentShakira) webview).canGoBack();
if (!goback)
super.onBackPressed();
}
}
}
片段:
public class FragmentShakira extends SherlockFragment {
static WebView webview;
String TAG = "webby";
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View view = inflater
.inflate(R.layout.fragmentwebview, container, false);
WebView webview = (WebView) view.findViewById(R.id.webView1);
webview.getSettings().setJavaScriptEnabled(true);
webview.setWebViewClient(new WebViewClient());
webview.loadUrl("https://www.google.co.uk/");
return view;
}
public boolean canGoBack() {
return webview != null && webview.canGoBack();
}
}
它应该会起作用。如果可能的话,不要忘记将消息传递给要返回的片段 即 使用由发布的代码。 下面是如何在代码中实现它。 在
onCreateView()方法中添加以下内容:
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View view = inflater
.inflate(R.layout.fragmentwebview, container, false);
WebView webview = (WebView) view.findViewById(R.id.webView1);
webview.getSettings().setJavaScriptEnabled(true);
webview.setWebViewClient(new WebViewClient());
webview.loadUrl("https://www.google.co.uk/");
//handles the back navigation in the fragment
webView.canGoBack();
webView.setOnKeyListener(new View.OnKeyListener() {
public boolean onKey(View v, int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_BACK
&& event.getAction() == MotionEvent.ACTION_UP
&& webView.canGoBack()) {
webView.goBack();
return true;
}
return false;
}
}); // until here
return view;
}
在Kotlin中,您可以通过添加到WebView来轻松处理此问题
override fun onViewCreated(view: View, savedInstanceState: Bundle?) {
super.onViewCreated(view, savedInstanceState)
val myWebView: WebView = view.findViewById(R.id.your_webView)
myWebView.webViewClient = WebViewClient()
myWebView.loadUrl("https://www.google.com/")
myWebView.setOnKeyListener { v, keyCode, event ->
if (keyCode == KeyEvent.KEYCODE_BACK && myWebView.canGoBack()) {
myWebView.goBack() // Navigate back to previous web page if there is one
nested_scroll.scrollTo(0, 0) // Scroll webview back to top of previous page
}
true
}
}
override fun onViewCreated(view: View, savedInstanceState: Bundle?) {
super.onViewCreated(view, savedInstanceState)
val myWebView: WebView = view.findViewById(R.id.your_webView)
myWebView.webViewClient = WebViewClient()
myWebView.loadUrl("https://www.google.com/")
myWebView.setOnKeyListener { v, keyCode, event ->
if (keyCode == KeyEvent.KEYCODE_BACK && myWebView.canGoBack()) {
myWebView.goBack() // Navigate back to previous web page if there is one
nested_scroll.scrollTo(0, 0) // Scroll webview back to top of previous page
}
true
}
}