Android &引用;如果;BroadcastReceiver服务上的in方法将不起作用
我在检查“if”中的变量时遇到问题。我从SharedReferences和SmsMessage的phoneNumber中获得一个userPhoneNumber变量 我将用这两个变量显示Toast,它们是相同的,但if不起作用。问题在哪里 我的广播接收器类别:Android &引用;如果;BroadcastReceiver服务上的in方法将不起作用,android,if-statement,service,broadcast,receiver,Android,If Statement,Service,Broadcast,Receiver,我在检查“if”中的变量时遇到问题。我从SharedReferences和SmsMessage的phoneNumber中获得一个userPhoneNumber变量 我将用这两个变量显示Toast,它们是相同的,但if不起作用。问题在哪里 我的广播接收器类别: public class IncomingSms extends BroadcastReceiver { String userPhoneNumber = ""; String senderNum= ""; String message=
public class IncomingSms extends BroadcastReceiver {
String userPhoneNumber = "";
String senderNum= "";
String message= "";
final String TAG="LocationService";
GPSTracker gps;
double latitude = 0.0;
double longitude = 0.0;
// Get the object of SmsManager
final SmsManager sms = SmsManager.getDefault();
public void onReceive(Context context, Intent intent) {
SharedPreferences settings = PreferenceManager.getDefaultSharedPreferences(context);
userPhoneNumber = settings.getString("userPhoneNumber", "");
Log.e(TAG, "userPhoneNumber:"+userPhoneNumber);
int duration = Toast.LENGTH_LONG;
// Retrieves a map of extended data from the intent.
final Bundle bundle = intent.getExtras();
try {
if (bundle != null) {
final Object[] pdusObj = (Object[]) bundle.get("pdus");
for (int i = 0; i < pdusObj.length; i++) {
SmsMessage currentMessage = SmsMessage.createFromPdu((byte[]) pdusObj[i]);
String phoneNumber = currentMessage.getDisplayOriginatingAddress().toString();
senderNum = phoneNumber;
message = currentMessage.getDisplayMessageBody();
turnOn(context);
} // end for loop
} // bundle is null
} catch (Exception e) {
Log.e("SmsReceiver", "Exception smsReceiver" +e);
}
Log.i("SmsReceiver", "senderNum: " + senderNum + "userPhoneNumber: "+ userPhoneNumber + "; message: " + message);
}
public void turnOn (Context context){
Intent i = new Intent(context, MyService.class);
gps = new GPSTracker(context);
Toast.makeText(context,"Method turnOn!\nsenderNum: "+senderNum + "\n userPhoneNumber: " + userPhoneNumber, Toast.LENGTH_LONG).show();
if (senderNum == userPhoneNumber) {
Toast.makeText(context,"works in IF", Toast.LENGTH_LONG).show();
if(gps.canGetLocation()){
latitude = gps.getLatitude();
longitude = gps.getLongitude();
i.putExtra("Latitude", latitude);
i.putExtra("Longitude", longitude);
context.startService(i);
}else
{
gps.showSettingsAlert();
}
}
gps.stopUsingGPS();
}
public class IncomingSms扩展广播接收器{
字符串userPhoneNumber=“”;
字符串senderNum=“”;
字符串消息=”;
最终字符串标记=“LocationService”;
全球定位系统;
双纬度=0.0;
双经度=0.0;
//获取SmsManager的对象
final smsmsmanager sms=smsmsmanager.getDefault();
公共void onReceive(上下文、意图){
SharedReferences设置=PreferenceManager.GetDefaultSharedReferences(上下文);
userPhoneNumber=settings.getString(“userPhoneNumber”,“userPhoneNumber”);
Log.e(标记“userPhoneNumber:”+userPhoneNumber);
int duration=Toast.LENGTH\u LONG;
//从意图检索扩展数据的映射。
final Bundle=intent.getExtras();
试一试{
if(bundle!=null){
最终对象[]pdusObj=(对象[])bundle.get(“pdus”);
对于(int i=0;i
senderNum这是一个字符串,表示您的if应该是:
if (senderNum.equals(userPhoneNumber))
您正在比较
senderNum
和userPhoneNumber
是否引用同一对象。您需要更改
if (senderNum == userPhoneNumber)
到
我认为问题出在这种情况下。 要比较字符串值,应使用equals()函数。 ==测试对象引用,.equals()测试字符串值 试一试
看谢谢!真的帮了大忙!
if (senderNum.equals(userPhoneNumber))
if (senderNum.equals(userPhoneNumber)) {
//code
}