获取android中内容的共享状态
我想在Android中共享内容,所以我使用以下代码进行共享:获取android中内容的共享状态,android,android-intent,android-sharing,Android,Android Intent,Android Sharing,我想在Android中共享内容,所以我使用以下代码进行共享: Intent sharingIntent = new Intent(Intent.ACTION_SEND); sharingIntent.setType("text/plain"); sharingIntent.putExtra( android.content.Intent.EXTRA_TEXT, message); startActivityForResult(Intent.createChooser( sharingIn
Intent sharingIntent = new Intent(Intent.ACTION_SEND);
sharingIntent.setType("text/plain");
sharingIntent.putExtra(
android.content.Intent.EXTRA_TEXT, message);
startActivityForResult(Intent.createChooser(
sharingIntent, "Share using"), 1000);
在onActivityResult()的中,我编写了以下代码:
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
Log.d("TAG", "::onActivityResult:" + "requestCode:" + requestCode
+ "resultCode:" + resultCode + "Data:" + data);
}
调用onActivityResult()
时,resultCode
始终是0
,这是因为ACTION\u SEND
未设置为与startActivityForResult()一起使用。ACTION\u SEND
的实现者不需要调用setResult()
,因此很少有人(如果有的话)会这样做
未设计用于startActivityForResult()