Android 5.0工具栏片段回退
我使用了appcompat库中的新工具栏来替换操作栏,并使用导航抽屉对其进行了设置 我的问题是,按back会最小化应用程序,而不是在Backback中循环。 如果我手动将逻辑添加到Android 5.0工具栏片段回退,android,android-fragments,android-5.0-lollipop,back-stack,android-toolbar,Android,Android Fragments,Android 5.0 Lollipop,Back Stack,Android Toolbar,我使用了appcompat库中的新工具栏来替换操作栏,并使用导航抽屉对其进行了设置 我的问题是,按back会最小化应用程序,而不是在Backback中循环。 如果我手动将逻辑添加到onBackPressed()以弹出后堆栈,这是一种解决方案,但会弄乱导航抽屉当前选定的项目 activity_main.xml <LinearLayout> <android.support.v7.widget.Toolbar/> <android.support.v
onBackPressed()
以弹出后堆栈,这是一种解决方案,但会弄乱导航抽屉当前选定的项目
activity_main.xml
<LinearLayout>
<android.support.v7.widget.Toolbar/>
<android.support.v4.widget.DrawerLayout>
<FrameLayout
android:id="@+id/container"
android:layout_width="match_parent"
android:layout_height="match_parent"/>
<ListView android:id="@+id/navigation_drawer"/>
</android.support.v4.widget.DrawerLayout>
</LinearLayout>
MainActivity.java
private void setupDrawerAndToolbar() {
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
final DrawerLayout drawerLayout = (DrawerLayout) findViewById(R.id.drawer_layout);
toggle = new ActionBarDrawerToggle(this, drawerLayout, toolbar,
R.string.app_name, R.string.app_name);
drawerLayout.setDrawerListener(toggle);
drawerList.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
onNavigationDrawerItemSelected(position, true);
drawerLayout.closeDrawer(GravityCompat.START);
}
});
List<NavigationDrawerItem> items = new ArrayList<>();
items.add(...);
drawerList.setAdapter(new NavigationDrawerAdapter(this, items));
drawerList.setItemChecked(selectedIndex, true);
}
...
private void onNavigationDrawerItemSelected(int position, boolean addToBackStack) {
if (position == selectedIndex) {
return;
}
selectedIndex = position;
// update the main content by replacing fragments
FragmentManager manager = getFragmentManager();
Fragment fragment;
switch (position) {
case ...:
fragment = new Fragment();
break;
default:
throw new IllegalArgumentException("invalid position");
}
FragmentTransaction transaction =
manager.beginTransaction()
.replace(R.id.container, fragment);
if (addToBackStack) {
transaction.addToBackStack(fragment.getClass().getName());
}
transaction.commit();
}
private void设置工具条(){
Toolbar Toolbar=(Toolbar)findViewById(R.id.Toolbar);
设置支持操作栏(工具栏);
最终抽屉布局抽屉布局=(抽屉布局)findViewById(R.id.抽屉布局);
toggle=新操作BarDrawerToggle(此、抽屉布局、工具栏、,
R.string.app_name,R.string.app_name);
抽屉布局。SetDroperListener(切换);
DroperList.setOnItemClickListener(新的AdapterView.OnItemClickListener(){
@凌驾
public void onItemClick(AdapterView父对象、视图、整型位置、长id){
onNavigationDrawerItemSelected(位置,true);
抽屉布局。关闭抽屉(重力公司启动);
}
});
列表项=新建ArrayList();
增加(……);
setAdapter(新的导航抽屉指针(this,items));
抽屉列表。setItemChecked(selectedIndex,true);
}
...
已选择NavigationDrawerItemSelected上的私有void(int位置,布尔addToBackStack){
如果(位置==所选索引){
返回;
}
selectedIndex=位置;
//通过替换片段更新主要内容
FragmentManager=getFragmentManager();
片段;
开关(位置){
案例…:
fragment=新片段();
打破
违约:
抛出新的IllegalArgumentException(“无效位置”);
}
零碎交易=
经理:开始营业()
.更换(R.id.容器、碎片);
if(addToBackStack){
transaction.addToBackStack(fragment.getClass().getName());
}
commit();
}
想出了一个解决办法:
private void onNavigationDrawerItemSelected(int position, boolean addToBackStack) {
if (position == selectedIndex) {
return;
}
// update the main content by replacing fragments
Fragment fragment;
switch (position) {
case ...:
fragment = new Fragment();
break;
default:
throw new IllegalArgumentException("invalid position");
}
FragmentTransaction transaction =
getFragmentManager().beginTransaction()
.replace(R.id.container, fragment, fragment.getClass().getName());
if (addToBackStack) {
transaction.addToBackStack(String.valueOf(selectedIndex));
}
transaction.commit();
selectedIndex = position;
}
...
@Override
public void onBackPressed() {
int count = getFragmentManager().getBackStackEntryCount();
if (count > 0) {
int index = Integer.parseInt(
getFragmentManager().getBackStackEntryAt(count - 1).getName());
getFragmentManager().popBackStack();
selectedIndex = index;
return;
}
super.onBackPressed();
}