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Android中的ListView错误_Android - Fatal编程技术网

Android中的ListView错误

Android中的ListView错误,android,Android,我是android新手,我想在我的布局和代码中显示列表视图,但它会引发致命错误,请建议我 活动代码: String [] frnds = {"Ajay Kumar", "Atul kumar", "Deepak Arora", "Mamta kri", "Mimi"}; ListView frndlist; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstance

我是android新手,我想在我的布局和代码中显示列表视图,但它会引发致命错误,请建议我

活动代码:

String [] frnds = {"Ajay Kumar", "Atul kumar", "Deepak Arora", "Mamta kri", "Mimi"};
ListView frndlist;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState); 
    //setListAdapter(new ArrayAdapter<String>(MainActivity.this,android.R.layout.simple_list_item_1, frnds));

    setContentView(R.layout.activity_main);
    frndlist = (ListView)findViewById(R.id.listView1);
    frndlist.setAdapter( new ArrayAdapter(MainActivity.this,android.R.layout.simple_list_item_1 ,frnds));

}
String[]frnds={“Ajay Kumar”、“Atul Kumar”、“Deepak Arora”、“Mamta kri”、“Mimi”};
列表视图frndlist;
@凌驾
创建时受保护的void(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
//setListAdapter(新的ArrayAdapter(MainActivity.this,android.R.layout.simple_list_item_1,frds));
setContentView(R.layout.activity_main);
frndlist=(ListView)findViewById(R.id.listView1);
setAdapter(新的ArrayAdapter(MainActivity.this,android.R.layout.simple_list_item_1,frnds));
}

我认为您遗漏了什么,请将代码更改为以下内容:

frndlist.setAdapter( new ArrayAdapter<String>(MainActivity.this,android.R.layout.simple_list_item_1 ,frnds));
frnlist.setAdapter(新的ArrayAdapter(MainActivity.this,android.R.layout.simple_list_item_1,frnds));

您需要向我们透露更多信息:错误详细信息和
activity\u main
xml布局