将字符串转换为Android JSONObject将丢失utf-8
我试图从URL获取一个(JSON格式的)字符串,并将其作为JSON对象使用。当我将字符串转换为JSONObject时,我丢失了UTF-8编码 这是我用来连接url并获取字符串的函数:将字符串转换为Android JSONObject将丢失utf-8,android,json,utf-8,jsonobject,Android,Json,Utf 8,Jsonobject,我试图从URL获取一个(JSON格式的)字符串,并将其作为JSON对象使用。当我将字符串转换为JSONObject时,我丢失了UTF-8编码 这是我用来连接url并获取字符串的函数: private static String getUrlContents(String theUrl) { StringBuilder content = new StringBuilder(); try { URL url = new URL(theUrl); UR
private static String getUrlContents(String theUrl) {
StringBuilder content = new StringBuilder();
try {
URL url = new URL(theUrl);
URLConnection urlConnection = url.openConnection();
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));
String line;
while ((line = bufferedReader.readLine()) != null) {
content.append(line + "\n");
}
bufferedReader.close();
} catch(Exception e) {
e.printStackTrace();
}
return content.toString();
}
从服务器获取数据时,以下代码显示正确的字符:
String output = getUrlContents(url);
Log.i("message1", output);
但是当我将输出字符串转换为JSONObject时,波斯语字符变成了问号,就像这样??????。(messages是JSON中数组的名称)
您告诉Java使用ISO-8859-1将字符串(带有键
message
)转换为字节,然后从这些字节创建一个新字符串,解释为UTF-8
new String(reader.getString("messages").getBytes("ISO-8859-1"), "UTF-8");
您可以简单地使用:
String messages = reader.getString("messages");
不确定这是否有帮助,但您可能可以这样做:
JSONObject result = null;
String str = null;
try
{
str = new String(output, "UTF-8");
result = (JSONObject) new JSONTokener(str).nextValue();
}
catch (Exception e) {}
String messages = result.getString("messages");
您可以按以下方式更新代码:
private static String getUrlContents(String theUrl) {
StringBuilder content = new StringBuilder();
try {
URL url = new URL(theUrl);
URLConnection urlConnection = url.openConnection();
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream(), "utf-8"));
String line;
while ((line = bufferedReader.readLine()) != null) {
content.append(line).append("\n");
}
bufferedReader.close();
} catch(Exception e) {
e.printStackTrace();
}
return content.toString().trim();
}
您有两个编码问题:
Content-type
HTTP响应中的charset
字段中给出。JSON通常是UTF-8编码的,但也可以是合法的UTF-16和UTF-32,因此需要检查。如果没有指定的编码,将字节编组为字符串时将使用系统环境,反之亦然。基本上,您应该始终指定字符集String messages=新字符串(reader.getString(“messages”).getBytes(“ISO-8859-1”),“UTF-8”)
显然会引起问题(如果您使用非ascii字符)-它将字符串编码为ISO-8995-1,然后尝试将其解码为UTF-8charset
值。我还包括了一个整洁的InputStream->String转换器
private static String getUrlContents(String theUrl) {
try {
URL url = new URL(theUrl);
URLConnection urlConnection = url.openConnection();
InputStream is = urlConnection.getInputStream();
// Get charset field from Content-Type header
String contentType = urlConnection.getContentType();
// matches value in key / value pair
Pattern encodingPattern = Pattern.compile(".*charset\\s*=\\s*([\\w-]+).*");
Matcher encodingMatcher = encodingPattern.matcher(contentType);
// set charsetString to match value if charset is given, else default to UTF-8
String charsetString = encodingMatcher.matches() ? encodingMatcher.group(1) : "UTF-8";
// Quick way to read from InputStream.
// \A is a boundary match for beginning of the input
return new Scanner(is, charsetString).useDelimiter("\\A").next();
} catch(Exception e) {
e.printStackTrace();
}
return null;
}
这是因为您通过线路接收的字节已在
getUrlContents
中正确解释,并在内部存储为UTF-16字符串。getUrlContents
仅当服务器的字符编码与客户端的字符编码匹配时才起作用。
private static String getUrlContents(String theUrl) {
try {
URL url = new URL(theUrl);
URLConnection urlConnection = url.openConnection();
InputStream is = urlConnection.getInputStream();
// Get charset field from Content-Type header
String contentType = urlConnection.getContentType();
// matches value in key / value pair
Pattern encodingPattern = Pattern.compile(".*charset\\s*=\\s*([\\w-]+).*");
Matcher encodingMatcher = encodingPattern.matcher(contentType);
// set charsetString to match value if charset is given, else default to UTF-8
String charsetString = encodingMatcher.matches() ? encodingMatcher.group(1) : "UTF-8";
// Quick way to read from InputStream.
// \A is a boundary match for beginning of the input
return new Scanner(is, charsetString).useDelimiter("\\A").next();
} catch(Exception e) {
e.printStackTrace();
}
return null;
}