Angular 在剑道网格ui中获取筛选器值
我有剑道格网Angular 在剑道网格ui中获取筛选器值,angular,typescript,kendo-ui,Angular,Typescript,Kendo Ui,我有剑道格网 <kendo-grid [data]="gridData" [pageSize]="state.take" [skip]="state.skip" [sort]="state.sort" [filter]="state.filter" filterable="menu" (dataStateChange)="dataStateChange($event)" > 我想在上面的函数中获取筛选值和字段名,并将它们传递给
<kendo-grid
[data]="gridData"
[pageSize]="state.take"
[skip]="state.skip"
[sort]="state.sort"
[filter]="state.filter"
filterable="menu"
(dataStateChange)="dataStateChange($event)"
>
我想在上面的函数中获取筛选值和字段名,并将它们传递给api进行服务器端筛选,但无法从状态中提取值
有没有办法从状态对象中提取字段和值?原语变量
import { isCompositeFilterDescriptor } from '@progress/kendo-data-query';
....
const filterValues = state.filter.filters.map(f => isCompositeFilterDescriptor(f) ? f.filters :[f] ).reduce((p,n) => p.concat(n), []);
但您应该检查“逻辑”字段,请参见属性“过滤器”在类型“CompositeFilterDescriptor | FilterDescriptor”上不存在。类型“FilterDescriptor”上不存在属性“filters”。第一个答案是JavaScript。更新了类型脚本检查的代码。完整代码在这里
import { isCompositeFilterDescriptor } from '@progress/kendo-data-query';
....
const filterValues = state.filter.filters.map(f => isCompositeFilterDescriptor(f) ? f.filters :[f] ).reduce((p,n) => p.concat(n), []);