Angular 如何比较es6中的两个对象

如何比较2个对象数组，当值匹配时，选中“角度材质”复选框？例如：在这种情况下，

operator

对象匹配，所以选中了operator的复选框

应用程序ts

const arr1 = [ 
   { 
      "id":"1",
      "name":"operator"
   },
   { 
      "id":"2",
      "name":"admins"
   }
]
const arr2 = [ 
   { 
      "id":"1",
      "name":"operator"
   },
   { 
      "id":"3",
      "name":"client"
   }
]

this.arr1.forEach(a1Obj => {
    this.arr2.some(a2Obj => {
        if (a2Obj.id === a1Obj.id) {
            console.log(a1Obj);
        }
    })
});

app.html

<div class="col" *ngFor="let group of groups; let i = index">
    <mat-checkbox value="group.id" [labelPosition]="'after'" [checked]="true" (change)="assignGroups($event, group.id)">
        {{ group.name }}
    </mat-checkbox>
</div>

{{group.name}

试试下面的方法

将阵列视为阵列1和阵列2

this.array1.forEach(a1Obj => {
    this.array2.some(a2Obj => {
        if (a2Obj.id === a1Obj.id) {
            console.log(a1Obj); // this object is there in array2 as well.
        }
    })
});