Warning: file_get_contents(/data/phpspider/zhask/data//catemap/2/ionic-framework/2.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Angularjs 如何在视图中使用HTML元素呈现基本HTML代码_Angularjs_Ionic Framework - Fatal编程技术网

Angularjs 如何在视图中使用HTML元素呈现基本HTML代码

Angularjs 如何在视图中使用HTML元素呈现基本HTML代码,angularjs,ionic-framework,Angularjs,Ionic Framework,我有一个html表单,如下所示: <div class=\"container\">\r\n\t<div class=\"clearfix row \">\r\n\t\t<div class=\"col-md-12 column\">\r\n\t\t\t<h3>\r\n\t\t\t\tNew form created\r\n\t\t\t<\/h3 >\r\n\t\t\t<div class=\"form-group\">\r

我有一个html表单,如下所示:

<div class=\"container\">\r\n\t<div class=\"clearfix row
\">\r\n\t\t<div class=\"col-md-12 column\">\r\n\t\t\t<h3>\r\n\t\t\t\tNew form created\r\n\t\t\t<\/h3
>\r\n\t\t\t<div class=\"form-group\">\r\n\t\t\t\t <label><strong>Enter   name<\/strong><\/label><input
name=\"1430985388220267#enter_name\" id=\"1430985388220267\" class=\"form-control\" grid-name=\"Enter
 name\" type=\"text\" \/>\r\n\t\t\t<\/div>\r\n\t\t<\/div>\r\n\t<\/div>\r\n<\/div>
我还修改了:

angular.module('iot', ['ionic','chart.js','ngSanitize'])
我将代码从REST响应推送到名为
HTML

但我仍然没有得到预期的产出,在这种情况下还有什么剩余?任何帮助都将不胜感激。

使用过滤器:

// Filter to enable HTML tags
app.filter('unsafe', function ($sce) {
    return function (val) {
        return $sce.trustAsHtml(val);
    };
});
然后将其与过滤器一起包含在HTML标记中(本例中为“不安全”),例如:

<!-- i.detail will be your valuable -->
<div ng-bind-html="i.detail | unsafe"></div>

您看到了什么?控制台有错误吗?
// Filter to enable HTML tags
app.filter('unsafe', function ($sce) {
    return function (val) {
        return $sce.trustAsHtml(val);
    };
});
<!-- i.detail will be your valuable -->
<div ng-bind-html="i.detail | unsafe"></div>