Angularjs 如何从包含模型中筛选环回中的字段？

我有一个疑问：

UserModel.find({

    filter: {
        include: 
        [
            "communications",
             "roles"
        ],
        where : {
            "object_type" : 1
        }
    } 
}, function(data){
    $rootScope.users = data;
});

我想通过字段“object_type”从通信模型过滤器中获取所有数据，但它不能按我所希望的那样工作

我的通信模型如下所示：

...
"properties": {
"object_type": {
  "type": "number"
},
"object_id": {
  "type": "number"
},
"communications_type_code": {
  "type": "number"
},
"address_type": {
  "type": "number"
},
"contact_value": {
  "type": "string"
},
"notes": {
  "type": "string"
},
....

UserModel.find({
    include: [ "communications", "roles" ],
    where : { "object_type" : 1 }
}, function(data){
    $rootScope.users = data;
});

---

Oded，我相信您不需要搜索参数中的

filter

属性。应该是这样写的：

...
"properties": {
"object_type": {
  "type": "number"
},
"object_id": {
  "type": "number"
},
"communications_type_code": {
  "type": "number"
},
"address_type": {
  "type": "number"
},
"contact_value": {
  "type": "string"
},
"notes": {
  "type": "string"
},
....

UserModel.find({
    include: [ "communications", "roles" ],
    where : { "object_type" : 1 }
}, function(data){
    $rootScope.users = data;
});

---

还要确保添加到

中的其他实体包括

与查询的模型有关系。是真的

UserModel

还是应该是

communicationmodel

？

要查询相关模型，您必须使用关系范围。在您的情况下，可能是这样的：

UserModel.find({
    filter: {
        include: 
        [
            {
              "relation": "communications",
              "scope": { 
                "where": {"object_type": 1}
              }

            },
            "roles"
        ]
    } 
}, function(data){
    $rootScope.users = data;
});

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