Ansible |如果目录为空,则创建符号链接

Ansible |如果目录为空,则创建符号链接,ansible,Ansible,我有一本这样的剧本: --- - hosts: all tasks: - name: Create 404 link file: dest: /var/www/html/{{ item }}/images/index.html src: /var/www/html/404.html state: link with_items: - a - b - c

我有一本这样的剧本:

---
- hosts: all
  tasks:
    - name: Create 404 link
      file:
        dest: /var/www/html/{{ item }}/images/index.html
        src: /var/www/html/404.html
        state: link
      with_items:
        - a
        - b
        - c
        - d
        - e
      # when: ???
...
现在,仅当
/var/www/html/{{{item}}/images
目录为空时,任务才应运行。
如何完成此操作?我尝试使用
find
模块和
register
提取输出,但未能成功提取其中没有文件的项(目录)。

找到了解决方案

---
- hosts: all
  tasks:
    - name: check contents of dir
      find:
        paths: "/var/www/html/{{ item }}/images/"
        patterns: "[A-Za-z0-9_-]+"
        use_regex: True
        file_type: any
        recurse: yes
      with_items:
        - a
        - b
        - c
        - d
        - e
      register: find_output

    - name: Create 404 link
      file:
        dest: /var/www/html/{{ item.item }}/images/index.html
        src: /var/www/html/404.html
        state: link
      with_items: "{{ find_output.results }}"
      when: item.matched == 0
...