antlr4木偶式声明语法问题
我正试图为木偶风格的声明性语言编写语法。我有我的基本语法,还有一个JUnit测试,试图实现一个侦听器方法来加载它。JUnit测试捕获第一个资源,但不捕获第二个资源,它几乎就像antlr4木偶式声明语法问题,antlr4,Antlr4,我正试图为木偶风格的声明性语言编写语法。我有我的基本语法,还有一个JUnit测试,试图实现一个侦听器方法来加载它。JUnit测试捕获第一个资源,但不捕获第二个资源,它几乎就像resources规则从未得到评估一样。我将日志语句添加到我的加载器中,资源永远不会进入/退出 grammar Bosse; resources : resource+; resource : ID LBRACE STRING COLON attributes RBRACE ; attribu
resources
规则从未得到评估一样。我将日志语句添加到我的加载器中,资源永远不会进入/退出
grammar Bosse;
resources : resource+;
resource : ID LBRACE STRING COLON attributes RBRACE ;
attributes : keyvalue ( COMMA keyvalue )* COMMA? ;
keyvalue : ID ASSIGN expr ;
expr : STRING
| INT
| FLOAT
;
ID : [a-z]+ ;
STRING : SQUOTE (SQESC|.)*? SQUOTE;
SQESC : '\\\'' | '\\\\' ;
INT : DIGIT+ ;
FLOAT : DIGIT+ '.' DIGIT*
| '.' DIGIT+
;
ASSIGN : '=>' ;
LBRACE : '{' ;
RBRACE : '}' ;
fragment
SQUOTE : '\'' ;
COLON : ':' ;
COMMA : ',' ;
WS : (' '|'\n'|'\t'|'\r')+ -> skip ;
fragment
DIGIT : [0-9] ;
我的BaseListener实现:
public class BosseLoader extends BosseBaseListener {
private List<Resource> resources = new ArrayList<Resource>();
private String resourceType;
private String resourceTitle;
private Map<String,Object> attributes = new HashMap<String,Object>();
private String parseString(String str) {
str = str.substring(1, str.length()-1);
str.replaceAll("\\\\(.)", "\1");
return str;
}
public List<Resource> getResources() {
return resources;
}
@Override
public void enterResources(ResourcesContext ctx) {
log.finest("entered "+ctx);
}
@Override
public void exitResources(ResourcesContext ctx) {
log.finest("entered "+ctx);
}
@Override
public void enterResource(ResourceContext ctx) {
log.finest("entered "+ctx);
resourceType = ctx.ID().getText();
resourceTitle = parseString(ctx.STRING().getText());
}
@Override
public void exitResource(ResourceContext ctx) {
log.finest("entered "+ctx);
Resource r = new Resource() {
public String getTitle() {
return resourceTitle;
}
public String toString() {
String type = resourceType.substring(0,1).toUpperCase()+resourceType.substring(1);
return type+"["+resourceTitle+"]";
}
};
resources.add(r);
System.out.println(r);
super.exitResource(ctx);
}
@Override
public void enterAttributes(AttributesContext ctx) {
log.finest("entered "+ctx);
attributes = new HashMap<String,Object>();
}
@Override
public void exitKeyvalue(KeyvalueContext ctx) {
log.finest("entered "+ctx);
attributes.put(ctx.ID().getText(),ctx.expr().getText());
}
}
我的测试输出:
testSyntaxDouble()
FINEST: AM org.cruck.bosse.language.BosseLoader enterResource entered []
FINEST: AM org.cruck.bosse.language.BosseLoader enterAttributes entered [19]
FINEST: AM org.cruck.bosse.language.BosseLoader exitKeyvalue entered [22 19]
FINEST: AM org.cruck.bosse.language.BosseLoader exitResource entered []
User[ruckc]
Failed tests:
testSyntaxDouble(org.cruck.bosse.language.BosseLanguageTest): expected:<2> but was:<1>
testSyntaxDouble()
最好的:AM org.cruck.bosse.language.BosseLoader enterResource已输入[]
最好的:AM org.cruck.bosse.language.BosseLoader enterAttributes已输入[19]
最精细:AM org.cruck.bosse.language.BosseLoader exitKeyvalue已输入[22 19]
最好的:AM org.cruck.bosse.language.BosseLoader exitResource已输入[]
用户[ruckc]
失败的测试:
testSyntaxDouble(org.cruck.bosse.language.BosseLanguageTest):应为:但为:
您正在调用parser.resource()
,但不应该是parser.resources()
(复数!)吗?哇。。。就这样。。。谢谢我现在觉得自己很愚蠢。
testSyntaxDouble()
FINEST: AM org.cruck.bosse.language.BosseLoader enterResource entered []
FINEST: AM org.cruck.bosse.language.BosseLoader enterAttributes entered [19]
FINEST: AM org.cruck.bosse.language.BosseLoader exitKeyvalue entered [22 19]
FINEST: AM org.cruck.bosse.language.BosseLoader exitResource entered []
User[ruckc]
Failed tests:
testSyntaxDouble(org.cruck.bosse.language.BosseLanguageTest): expected:<2> but was:<1>