Apache drill 如何使用ApacheDrill展平两个json数组

我有上面的json，我想展平batter和topping数组

所以我试着做：

{
    "id": "0001",
    "type": "donut",
    "name": "Cake",
    "ppu": 0.55,
    "batters":
        {
            "batter":
                [
                    { "id": "1001", "type": "Regular" },
                    { "id": "1002", "type": "Chocolate" },
                    { "id": "1003", "type": "Blueberry" },
                    { "id": "1004", "type": "Devil's Food" }
                ]
        },
    "topping":
        [
            { "id": "5001", "type": "None" },
            { "id": "5002", "type": "Glazed" },
            { "id": "5005", "type": "Sugar" },
            { "id": "5007", "type": "Powdered Sugar" },
            { "id": "5006", "type": "Chocolate with Sprinkles" },
            { "id": "5003", "type": "Chocolate" },
            { "id": "5004", "type": "Maple" }
        ]
}

这让我

org.apache.drill.common.exceptions.UserRemoteException:验证 错误：从第1行第43列到第1行第49列：表格“batters” 找不到SQL查询空[错误Id: 宏碁上的33cf80f2-f283-4401-90ce-c262474e0778:31010]

---

我怎样才能解决这个问题？我们可以在一个查询中展平两个数组吗？

您需要添加表别名并在列中引用它。下面的查询使用您提供的示例数据对我有效

SELECT flatten(topping) as toping,flatten(batters.batter) as bat  FROM json.jsonfiles.`batter.json`;

SELECT flatten(a.topping) as toping,flatten(a.batters.batter) as bat  FROM  dfs.tmp.`batter.json` a;