快速api和颤振

尝试在占星术应用程序中使用此api，虽然该食谱不适用于Flitter，但我正在尝试启动一个请求。 如果您能从rapid api获得这些数据并将其应用于颤振，我们将不胜感激，因为目前还没有相关的文档

import 'dart:convert';
import 'package:http/http.dart' as http;


class APIService {
  // API key
  // Base API url
  static const String _baseUrl = "https://sameer-kumar-aztro-v1.p.rapidapi.com/?sign=aquarius&day=today";
  // Base headers for Response url
  static const Map<String, String> _headers = {
  "x-rapidapi-key": "*****************",
    "x-rapidapi-host": "sameer-kumar-aztro-v1.p.rapidapi.com",
    
  };

  // Base API request to get response
  Future<dynamic> get() async {
    Uri uri = Uri.https(_baseUrl,"");
    final response = await http.get(uri, headers: _headers);
    if (response.statusCode == 200) {
      // If server returns an OK response, parse the JSON.
      print("success");
      return json.decode(response.body);
    } else {
      print("not success");
      // If that response was not OK, throw an error.
      throw Exception('Failed to load json data');
    }
  }
}

试试这个

Uri uri = Uri.parse(_baseUrl);
final response = await http.get(uri, headers: _headers);

---

不再使用get-use-post命令..

现在获取：403 E/flatter（27257）：[ERROR:flatter/lib/ui/ui\u dart\u state.cc（186）]未处理的异常：异常：加载json数据失败感谢您这么多，它成功了

Uri uri = Uri.parse(_baseUrl);
final response = await http.get(uri, headers: _headers);