Arrays 从数组中删除项 如何删除数组中间的一个项？我试过这个： Public Sub RemoveArrayElement(AryVar() As Object, ByVal RemoveWhich As Long) Dim byteLen As Byte byteLen = 4 If RemoveWhich < UBound(AryVar) Then CopyMemory ByVal VarPtr(AryVar(RemoveWhich)), ByVal _ VarPtr(AryVar(RemoveWhich + 1)), (byteLen) * _ (UBound(AryVar) - RemoveWhich) End If If UBound(AryVar) = LBound(AryVar) Then Erase AryVar Else ReDim Preserve AryVar(UBound(AryVar) - 1) End If End Sub 公共子RemoveArrayElement（AryVar（）作为对象，ByVal RemoveWhich作为长） Dim byteLen作为字节 byteLen=4 如果移除哪个

但是，当我从

aryvar

检索项时，它返回

Nothing

的方法与上面的方法稍有不同，但您不能将所有值向下移动，然后收缩数组吗

例如：

Public Sub RemoveArrayElement(AryVar() As Object, ByVal RemoveWhich As Long)
    If UBound(AryVar) > 0 Then
        Dim i As Integer
        For i = LBound(AryVar) To UBound(AryVar) - 1
            If i >= removeWhich Then
                    AryVar(i) = AryVar(i + 1)
            End If
        Next
        ReDim Preserve AryVar(UBound(AryVar) - 1)
    End If
End Sub

另一种方法是：

'1 form with:
'  1 command button: name=Command1

Option Explicit

Private Sub Command1_Click()
  Dim intIndex As Integer
  'dim an array with undefined boundaries
  Dim intArray() As Integer
  'set boundaries
  ReDim intArray(10) As Integer
  'fill array with values
  For intIndex = 0 To 10
    intArray(intIndex) = intIndex * intIndex
  Next intIndex
  'show the data from the initial array
  ShowArray intArray
  'remove the 6th item (index=5)
  intArray = RemoveItem(5, intArray)
  'show the data of the resulting array (with the 6h item removed)
  ShowArray intArray
End Sub

Private Function RemoveItem(intItem As Integer, intSrc() As Integer) As Integer()
  Dim intIndex As Integer
  Dim intDest() As Integer
  Dim intLBound As Integer, intUBound As Integer
  'find the boundaries of the source array
  intLBound = LBound(intSrc)
  intUBound = UBound(intSrc)
  'set boundaries for the resulting array
  ReDim intDest(intLBound To intUBound - 1) As Integer
  'copy items which remain
  For intIndex = intLBound To intItem - 1
    intDest(intIndex) = intSrc(intIndex)
  Next intIndex
  'skip the removed item
  'and copy the remaining items, with destination index-1
  For intIndex = intItem + 1 To intUBound
    intDest(intIndex - 1) = intSrc(intIndex)
  Next intIndex
  'return the result
  RemoveItem = intDest
End Function

Private Sub ShowArray(intArray() As Integer)
  Dim intIndex As Integer
  'print all items to the form to show their value
  For intIndex = LBound(intArray) To UBound(intArray)
    Print "Item " & CStr(intIndex) & " : " & CStr(intArray(intIndex))
  Next intIndex
  'print an empty line to separate the arrays in displaying
  Print
End Sub

区别在于：

• 返回数组而不是传递byref
• 使用暗显为正确大小的临时阵列，而不是在末尾使用redim PREVICE
• 复制保留相同索引的项目，并仅移动删除项目后的项目

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这个代码片段可能会对您有所帮助

Dim remove_place As Integer
Dim ar() As Integer
Dim n As Integer
n = 10
ReDim ar(n)                     'Initial size of an array
remove_place = Val(Text1.Text)  'This is the position to be deleted
For i = remove_place To n - 1
ar(i) = ar(i + 1)               'This loop will shift array position one    place   to the left. This way the number at your position will be replaced by the next number.
Next
ReDim Preserve ar(n - 1)        'I guess you know what it means.

---

将其置于任何事件过程下。
这看起来像vb.net。问题被标记为vb6。@C-PoundGuru它确实是vb6，vb6中不支持“i作为整数”为什么有文本框？我没听说过，这只是一个演示。我使用文本框通过文本框获取用户的位置。你可以采取任何其他选择。那要看你了。这个程序只是为了演示“删除”算法。