Assembly 美国电话电报公司；T语法错误：垃圾'；（限制性商业惯例）和#x27；组装incq-8（rbp）时表达后

我在编译代码时遇到了这些错误，我不知道为什么。谁能帮帮我吗。我在用AT&T的语法写作 错误：inout子例程中带***的行上的表达式后出现错误垃圾（rbp）

代码：

.text                   #section directive intended to hold all instructions

formatint:  .asciz  "%ld"

formatstr:  .asciz  "%s"        #format string for string printing, the s stands for string

DNNIDA:     .asciz          "names: x and y \nnetID's: xID and yID\nThis is assignment 1b inout\n"   
enter:      .asciz          "\n"



.global main                #this is the main label


main:

    movq    $0, %rax        #no vector registers in use for printf (labmanual)
    movq    $formatstr, %rdi   
    movq    $DNNIDA, %rdi       #load adress of string to rdi register
    call    printf          #printing the string that is displayed on top

    call    inout           #calling the inout subroutine

    movq    $0, %rax        #no vector registers in use for printf (labmanual)
    movq    $formatstr, %rdi
    movq    $enter, %rdi        #load the adress off the next string into rdi register
    call    printf          #printing the enter string (a return)
    call    end

end:

    mov     $0, %rdi        #load program exit code
    call        exit            #exiting the program

inout:

    pushq   %rbp            #Prologue: push the base pointer   
    movq    %rsp, %rbp      #copy stack pointer to RBP

    subq    $8, %rsp        #reserve stack space for variable
    leaq    -8(%rbp), %rsi      #load adress of stack var in rsi
    movq    $formatint, %rdi    #load first argument of scanf
    movq    $0, %rax        #no vector registers in use for printf (labmanual)
    call    scanf           #call scanf

    movq    $formatint, %rdi
    movq    $0, %rax        #no vector registers in use for printf (labmanual)
    ***incq    -8(rbp)         #increments the number by one

    ***movq    -8(rbp), %rsi       #move a return value into RAX
    call    printf          #call printf
    movq    %rbp, %rsp      #Epilogue: clear local variables from stack
    popq    %rbp            #Restore caller's base pointer
    ret             #returns from subroutine

---

我认为

%

丢失了。我在哪里丢失了%？发生错误的行是您使用

rbp

而不是

%rbp

的唯一行。是的，谢谢。我想我拿到的手册有错误。Anways THANKS没有问题：）我对AT&T的语法不是很精通，但这似乎很奇怪。我认为

%

丢失了。我在哪里丢失了%？发生错误的行是您使用

rbp

而不是

%rbp

的唯一行是的，谢谢。我想我拿到的手册有错误。Anways thanksNo问题：）我对AT&T的语法不是很精通，但这似乎很奇怪。