使用AWK从文件名字段中删除引号
我已经花了一个小时来研究这个问题，试图找出如何使用AWK嵌入删除特定字段中的引号 基本上，该文件用引号封装文本，但我想使用第二个字段命名该文件，并基于第一个字段拆分它们使用AWK从文件名字段中删除引号,awk,Awk,我已经花了一个小时来研究这个问题，试图找出如何使用AWK嵌入删除特定字段中的引号 基本上，该文件用引号封装文本，但我想使用第二个字段命名该文件，并基于第一个字段拆分它们 ID,Name,Value1,Value2,Value3 1,"AAA","DEF",1,2 1,"AAA","GGG",7,9 2,"BBB","DEF",1,2 2,"BBB","DEF",9,0 3,"CCC","AAA",1,1 我想要得到的是三个文件，所有文件的标题行都命名为： AAA [1].csv BBB [2]
ID,Name,Value1,Value2,Value3
1,"AAA","DEF",1,2
1,"AAA","GGG",7,9
2,"BBB","DEF",1,2
2,"BBB","DEF",9,0
3,"CCC","AAA",1,1
AAA [1].csv
BBB [2].csv
CCC [3].csv
awk -F, 'NR==1{h=$0;next}!($1 in files){evname=$2" ["$1"].csv";files[$1]=1;print h>evname}{print > evname}' DataExtract.csv
awk -F, 'NR==1{h=$0;next}!($1 in files){evname=gsub(""\","", $2)" - Event ID ["$1"].csv";files[$1]=1;print h>evname}{print > evname}' DataExtract.csv
甘农如果我正确理解您的尝试，那么
awk -F, 'NR==1{h=$0;next}!($1 in files){gsub(/"/, "", $2); evname=$2" ["$1"].csv";files[$1]=1;print h>evname}{print > evname}' DataExtract.csv
NR == 1 {
h = $0;
next
}
!($1 in files) {
stub = $2 # <-- this is the new bit: make a working copy
# of $2 (so that $2 is unchanged and the line
# is not rebuilt with changes for printing),
gsub(/"/, "", stub) # remove the quotes from it, and
evname = stub " [" $1 "].csv" # use it to assemble the filename.
files[$1] = 1;
print h > evname
}
{
print > evname
}
gsubevname=gsub（“\”，“，$2）”-事件ID[“$1”].csv“awk -F, 'NR==1{h=$0;next}!($1 in files){gsub(/"/, "", $2); evname=$2" ["$1"].csv";files[$1]=1;print h>evname}{print > evname}' DataExtract.csv
NR == 1 {
h = $0;
next
}
!($1 in files) {
stub = $2 # <-- this is the new bit: make a working copy
# of $2 (so that $2 is unchanged and the line
# is not rebuilt with changes for printing),
gsub(/"/, "", stub) # remove the quotes from it, and
evname = stub " [" $1 "].csv" # use it to assemble the filename.
files[$1] = 1;
print h > evname
}
{
print > evname
}
gsubevname=gsub（“\”，“，$2）”-事件ID[“$1”].csv“awk -F, 'NR==1{h=$0;next}
!($1 in files){
gsub("\"","",$2); # Add this line
evname=$2" ["$1"].csv";files[$1]=1;print...
在进行分配之前应用gsub：
awk -F, 'NR==1{h=$0;next}
!($1 in files){
gsub("\"","",$2); # Add this line
evname=$2" ["$1"].csv";files[$1]=1;print...
只要有一点空白，事情就会变得更清楚：
awk -F, '
NR==1 { hdr=$0; next }
!seen[$1]++ {
evname = $2
gsub(/"/,"",evname)
outfile = evname " [" $1 "].csv"
print hdr > outfile
}
{ print > outfile }
' DataExtract.csv
awk -F, '
NR==1 { hdr=$0; next }
!seen[$1]++ {
outfile = gensub(/"/,"","g",$2) " [" $1 "].csv"
print hdr > outfile
}
{ print > outfile }
' DataExtract.csv
只要有一点空白，事情就会变得更清楚：
awk -F, '
NR==1 { hdr=$0; next }
!seen[$1]++ {
evname = $2
gsub(/"/,"",evname)
outfile = evname " [" $1 "].csv"
print hdr > outfile
}
{ print > outfile }
' DataExtract.csv
awk -F, '
NR==1 { hdr=$0; next }
!seen[$1]++ {
outfile = gensub(/"/,"","g",$2) " [" $1 "].csv"
print hdr > outfile
}
{ print > outfile }
' DataExtract.csv
你的产出应该是什么样子还不是很清楚。你能澄清一下吗？你的产出应该是什么样子还不是很清楚。你能澄清一下吗？啊，我以为gsub忽略了我想要2美元的事实，只是给了我2美元，但我不认为是因为有两种替代品。这非常接近我需要的……o唯一的问题是文件的内容从$2中删除了封装，并且第一行值（在打印h之后）也删除了所有逗号。数据行2-n（即文件行3-n）看起来正确（封装并用逗号分隔）。有没有办法只删除文件名中使用的引号，而不删除打印到相关文件的引号？
tmp=$2；gsub（/“/，”，tmp）；evname=tmp“-Event ID[“$2”].csv”$2tmp=$2；gsub（/“/，”，tmp）；evname=tmp“-Event ID[“$2”].csv”$2