Awk 我想检查第1列中的数字是否等于第2列。第1列应以以下格式开始和结束

我想检查第1列中的数字是否等于第2列，最后第1列应该以

“ABC”

开头，以

“DEF”

结尾，但有时它也以

“DEFZ”

结尾，介于

“ABC”和
“DEF”
之间的数字应该与第2列匹配。有人能帮我吗

我的输入：

ABC12345DEF|12345|23132331331|
ABC12345DEFZ1|12345|23132331331|
ABC12345DEFZ2|12345|23132331331|
ABC95678DEF|45678|23132331331| 
ABC87887DEF|86187|23132331331|
ABC89043DEF|89043|23132331331|
ABC89043DEFZ1|89043|23132331331|
ABC89043DEFZ2|89043|23132331331|
ABC89043DEFZ3|89043|23132331331|

ABC12345DEF|12345|23132331331|
ABC12345DEFZ1|12345|23132331331|
ABC12345DEFZ2|12345|23132331331|
ABC89043DEFZ1|89043|23132331331|    
ABC89043DEFZ2|89043|23132331331|
ABC89043DEFZ3|89043|23132331331|

输出应为：

ABC12345DEF|12345|23132331331|
ABC12345DEFZ1|12345|23132331331|
ABC12345DEFZ2|12345|23132331331|
ABC95678DEF|45678|23132331331| 
ABC87887DEF|86187|23132331331|
ABC89043DEF|89043|23132331331|
ABC89043DEFZ1|89043|23132331331|
ABC89043DEFZ2|89043|23132331331|
ABC89043DEFZ3|89043|23132331331|

ABC12345DEF|12345|23132331331|
ABC12345DEFZ1|12345|23132331331|
ABC12345DEFZ2|12345|23132331331|
ABC89043DEFZ1|89043|23132331331|    
ABC89043DEFZ2|89043|23132331331|
ABC89043DEFZ3|89043|23132331331|

我正在尝试使用下面的一个，但它不起作用

awk -F '|' '"ABC" $2 "DEF" == $1 && "ABC" $2 "DEFZ"+[0-9] == $1 { print }' WHTFile.txt > QC2Valid.txt**

有人能帮我吗？
提前谢谢

awk -v FS="|" '{tmpvar=$1;gsub(/^ABC|DEF(Z[0-9]+)?$/,"",tmpvar)}tmpvar == $2' infile

输入

akshay@db-3325:/tmp$ cat infile
ABC12345DEF|12345|23132331331|
ABC12345DEFZ1|12345|23132331331|
ABC12345DEFZ2|12345|23132331331|
ABC95678DEF|45678|23132331331|
ABC87887DEF|86187|23132331331|
ABC89043DEF|89043|23132331331|
ABC89043DEFZ1|89043|23132331331|
ABC89043DEFZ2|89043|23132331331|
ABC89043DEFZ3|89043|23132331331|

akshay@db-3325:/tmp$ awk -v FS="|" '{tmpvar = $1; gsub(/^ABC|DEF(Z[0-9]+)?$/,"",tmpvar)} tmpvar == $2' infile
ABC12345DEF|12345|23132331331|
ABC12345DEFZ1|12345|23132331331|
ABC12345DEFZ2|12345|23132331331|
ABC89043DEF|89043|23132331331|
ABC89043DEFZ1|89043|23132331331|
ABC89043DEFZ2|89043|23132331331|
ABC89043DEFZ3|89043|23132331331|

输出

akshay@db-3325:/tmp$ cat infile
ABC12345DEF|12345|23132331331|
ABC12345DEFZ1|12345|23132331331|
ABC12345DEFZ2|12345|23132331331|
ABC95678DEF|45678|23132331331|
ABC87887DEF|86187|23132331331|
ABC89043DEF|89043|23132331331|
ABC89043DEFZ1|89043|23132331331|
ABC89043DEFZ2|89043|23132331331|
ABC89043DEFZ3|89043|23132331331|

akshay@db-3325:/tmp$ awk -v FS="|" '{tmpvar = $1; gsub(/^ABC|DEF(Z[0-9]+)?$/,"",tmpvar)} tmpvar == $2' infile
ABC12345DEF|12345|23132331331|
ABC12345DEFZ1|12345|23132331331|
ABC12345DEFZ2|12345|23132331331|
ABC89043DEF|89043|23132331331|
ABC89043DEFZ1|89043|23132331331|
ABC89043DEFZ2|89043|23132331331|
ABC89043DEFZ3|89043|23132331331|

解释

awk -v FS="|" '{                  # call awk set field separator |
                 tmpvar = $1;     # save first field contents in variable tmpvar

                 # substitute first ABC or DEF 
                 # which can be followed by Z and numbers 
                 # from variable with null globally
                 # so that tmpvar will just have numbers which is between abc and def*
                 gsub(/^ABC|DEF(Z[0-9]+)?$/,"",tmpvar)
               } 
               # if tmpvar is equal to second field then
               # print current record/row/line, thats boolean true, print $0
               tmpvar == $2
              ' infile



/^ABC | DEF（Z[0-9]+）？/
1st Alternative
^ABC
^
断言字符串开头的位置
ABC
与字符
ABC
逐字匹配（区分大小写）

第二个备选方案
DEF（Z[0-9]+）？
DEF
匹配字符
DEF
字面上（区分大小写）第一个捕获组
（Z[0-9]+）？
？
量词-匹配0到1次，尽可能多次，根据需要返回（贪婪）
Z
匹配字符
Z
字面意思（区分大小写）匹配下表中的单个字符
[0-9]+

+
量词-在一次和无限次之间进行匹配，尽可能多地匹配，根据需要返回（贪婪）

嘿，阿凯，一切正常，非常感谢，非常感谢。当然，谢谢你，阿凯