如何在匹配模式后打印下一行，然后在使用awk再次出现匹配模式时停止打印？

我有一个SQL文件，格式如下：

-- 1. Create a view 'c_summary' summarizing campaign contributions,
-- with four attributes: cand_name, contbr_name, amount, and zip. 

create view c_summary as
  select candidate.name as cand_name, contributor.name as contbr_name, amount, zip
    from candidate inner join contributor inner join contribution
      on candidate.cand_id = contribution.cand_id and
         contributor.contbr_id = contribution.contbr_id;

-- 2. For each of the occupations "STUDENT", "TEACHER", and "LAWYER",
-- show the occupation, and average size (in dollars) of contribution
-- from contributors with that occupation.

select occupation, round(avg(amount))
  from contributor natural join contribution
  where occupation in ("STUDENT", "TEACHER", "LAWYER")
  group by occupation;

仅当问题编号作为编号提供给

PROB

变量时，我才试图打印出包含查询的行，然后在遇到另一个问题时停止

例如，我希望第二个问题的输出如下：

$ awk -f get_query.awk -v PROB=2 queries.sql
select occupation, round(avg(amount))
 from contributor natural join contribution
 where occupation in ("STUDENT", "TEACHER", "LAWYER")
 group by occupation;

$ awk -f get_query.awk -v PROB=1 queries.sql
create view c_summary as
  select candidate.name as cand_name, contributor.name as contbr_name, amount, zip
    from candidate inner join contributor inner join contribution
      on candidate.cand_id = contribution.cand_id and
         contributor.contbr_id = contribution.contbr_id;

或者，第一个问题的输出如下：

$ awk -f get_query.awk -v PROB=2 queries.sql
select occupation, round(avg(amount))
 from contributor natural join contribution
 where occupation in ("STUDENT", "TEACHER", "LAWYER")
 group by occupation;

$ awk -f get_query.awk -v PROB=1 queries.sql
create view c_summary as
  select candidate.name as cand_name, contributor.name as contbr_name, amount, zip
    from candidate inner join contributor inner join contribution
      on candidate.cand_id = contribution.cand_id and
         contributor.contbr_id = contribution.contbr_id;

我尝试了以下操作，但得到的输出不是我想要的：

/^--/{
    RS="-- "
    getline
}
$0 ~ PROB{
    print $0
}

如何修改我的

awk

脚本以获得所需的输出？

编辑：添加代码以删除我以前代码中的控件M字符，因为OP的输入文件中有控件M字符

awk -v PROB=1 '{gsub(/\r/,"")} /^-/{next} !/^ +/&&!/^$/{count++}  count==PROB && NF' Input_file

---

请您尝试以下内容，并让我知道这是否有助于您

awk -v PROB=2 '/^-/{next} !/^ +/&&!/^$/{count++}  count==PROB && NF'  Input_file

如果您给出

PROB=1

，则以下为输出

awk -v PROB=1 '/^-/{next} !/^ +/&&!/^$/{count++}  count==PROB && NF' Input_file

说明：

awk -v PROB=2 '                  ##Creating a variable named PROB whose value is 2 here.
/^-/             {  next     }   ##Checking if a line starts from dash then using next it will skip all further statements.
!/^ +/ && !/^$/  {  count++  }   ##Checking if a line not starts from space and is NOT a NULL line then increase the value of variable named count to 1.
count==PROB && NF                ##Checking condition here if variable count value is equal to variable PROB and line is NOT an empty line then print it.
' Input_file                     ##Mentioning the Input_file name here.

---

请在您的帖子中的代码标签中发布预期输出。问题中提供了预期输出。我希望它输出每个问题的查询。因此，对于第一个问题，我会这样做：

$awk-f get\u query.awk-v PROB=1 querys.sql

只获取sql查询。这意味着您不需要以

-

等开头的行？是的，对于awk声明中给定给

PROB

的特定问题编号，我试图仅获取不以

-

开头的行。请检查我的答案，并让我知道这是否有帮助？现在删除上述代码的输出，只保留其中的代码和解释。当我尝试在具有awk版本的机器上运行此操作时3.1.7我没有得到我想要的输出。有可能使它与那个版本兼容吗？@Grey，即使是我的版本也太

GNU Awk 3.1.7

了，而且对我来说工作得很好。这真的很奇怪。当我试图运行它时，我得到一个空行作为输出。@Grey，也检查

cat-v输入\ u文件

是否在其中看到任何控件M字符？如果是，请务必在同一时间通知我。