Backbone.js:Collection.Get(id)->;忽略案例
我有以下型号和系列:Backbone.js:Collection.Get(id)->;忽略案例,backbone.js,Backbone.js,我有以下型号和系列: var UserModel = Backbone.Model.extend({ url: 'api/user', idAttribute:'username', defaults: { username:'', password:'', email:'', tags:'' } }); var UserCollection= Backbone.Collection.extend({
var UserModel = Backbone.Model.extend({
url: 'api/user',
idAttribute:'username',
defaults: {
username:'',
password:'',
email:'',
tags:''
}
});
var UserCollection= Backbone.Collection.extend({
url: 'api/user',
model: UserModel
});
当我使用以下命令从集合中检索用户时:
var myUser = collection.get(username);
用户名的大小写必须正确,否则结果就是null
有没有一种方法可以告诉主干网,对于像这样的操作,忽略案例?当然,您只需要更改相关代码。它位于
backbone.js
的240-242
行(对于文档化的0.9.2版本):
将其更改为:
get: function(attr) {
// will skip if null or undefined -- http://stackoverflow.com/questions/5113374/javascript-check-if-variable-exists-which-method-is-better
if (this.attributes[attr] != null) {
return this.attributes[attr];
}
// and then try to return for capitalized version -- http://stackoverflow.com/questions/1026069/capitalize-the-first-letter-of-string-in-javascript
else {
return this.attributes[attr.charAt(0).toUpperCase() + attr.slice(1)];
}
},
更改收藏
get: function(id) {
if (id == null) return void 0;
return this._byId[id.id != null ? id.id : id];
},
这样做可能会奏效:
get: function(id) {
if (id == null) return void 0;
var firstCase = this._byId[id.id != null ? id.id : id];
if (firstCase != null) {
return firstCase;
}
else {
return this._byId[capitalize(id.id) != null ? capitalize(id.id) : capitalize(id)];
}
},
更好的方法是使用
Backbone.Model.extend({})
并覆盖那里的get
。您可以代理到Backbone.Model.prototype.get.call(this,lowercaseId)
并确保行为正确。
get: function(id) {
if (id == null) return void 0;
var firstCase = this._byId[id.id != null ? id.id : id];
if (firstCase != null) {
return firstCase;
}
else {
return this._byId[capitalize(id.id) != null ? capitalize(id.id) : capitalize(id)];
}
},