Java me 如何解决j2me中ProximityListener的LocationException_Java Me_Jsr179

Java me 如何解决j2me中ProximityListener的LocationException

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Java me 如何解决j2me中ProximityListener的LocationException,java-me,jsr179,Java Me,Jsr179,我的addProximityListener代码是- Coordinates proxcoord = new Coordinates(0.0, 0.0, 0.0f); proxcoord.setLatitude(Double.parseDouble(lat)); proxcoord.setLongitude(Double.parseDouble(lon)); provider.addProximityListener(this, proxcoord, 40.0f); 将ProximityL

我的addProximityListener代码是-

Coordinates proxcoord = new Coordinates(0.0, 0.0, 0.0f); 
proxcoord.setLatitude(Double.parseDouble(lat));
proxcoord.setLongitude(Double.parseDouble(lon));
provider.addProximityListener(this, proxcoord, 40.0f);

将ProximityListener添加到位置提供程序平台时，显示了一个错误，如下所示-

javax.microedition.location.LocationException
at javax.microedition.location.LocationProvider.addProximityListener(+7)
at mobilelocationreminder.MobileLocationReminder.commandAction(+4414)
at javax.microedition.lcdui.Displayable.callKeyPressed(+269)
at javax.microedition.lcdui.Form.callKeyPressed(+243)
at javax.microedition.lcdui.Display.consumeUIEvent(+101)
at javax.microedition.lcdui.Display$DisplayAccessor.consumeEvent(+117)
null

我在文档中看到了它的错误含义 LocationException-如果平台没有资源添加新的侦听器和要监视的坐标，或者根本不支持接近监视

但我不明白如何解决这个问题