如何为bash中的函数指定一个空数组？

我正在学习bash。 现在我想给一个函数一个空数组。但是，它不起作用。请参考以下内容：

function display_empty_array_func() {
  local -a aug1=$1
  local -a aug2=${2:-no input}
  echo "array aug1 = ${aug1[@]}"
  echo "array aug2 = ${aug2[@]}"
}

declare -a empty_array=()

display_empty_array_func "${empty_array[@]}" "1"

array aug1 = 1  # I expected it is empty
array aug2 = no input  # I expected it is 1

function display_empty_variable_func() {  
  local aug1=$1
  local aug2=${2:-no input}
  echo "variable aug1 = ${aug1}"
  echo "variable aug2 = ${aug2}"
}

display_empty_variable_func "" "1"

产出如下：

function display_empty_array_func() {
  local -a aug1=$1
  local -a aug2=${2:-no input}
  echo "array aug1 = ${aug1[@]}"
  echo "array aug2 = ${aug2[@]}"
}

declare -a empty_array=()

display_empty_array_func "${empty_array[@]}" "1"

array aug1 = 1  # I expected it is empty
array aug2 = no input  # I expected it is 1

function display_empty_variable_func() {  
  local aug1=$1
  local aug2=${2:-no input}
  echo "variable aug1 = ${aug1}"
  echo "variable aug2 = ${aug2}"
}

display_empty_variable_func "" "1"

根据我的理解，引用变量允许我们给出一个空变量， 像下面这样,

function display_empty_array_func() {
  local -a aug1=$1
  local -a aug2=${2:-no input}
  echo "array aug1 = ${aug1[@]}"
  echo "array aug2 = ${aug2[@]}"
}

declare -a empty_array=()

display_empty_array_func "${empty_array[@]}" "1"

array aug1 = 1  # I expected it is empty
array aug2 = no input  # I expected it is 1

function display_empty_variable_func() {  
  local aug1=$1
  local aug2=${2:-no input}
  echo "variable aug1 = ${aug1}"
  echo "variable aug2 = ${aug2}"
}

display_empty_variable_func "" "1"

其产出如下

variable aug1 =    # it is empty as expected
variable aug2 = 1  # it is 1 as expected

我不知道传递am空数组有什么问题。 了解机制或解决方案的人。请告诉我。 非常感谢。

如果位置参数为空，shell脚本和shell函数将不考虑该值，而是将下一个非空值作为其值（位置参数值）。 如果我们想取空值，我们必须将该值用引号括起来

Ex: I'm having small script like 
cat test_1.sh
#!/bin/bash

echo "First Parameter is :"$1;

echo "Second Parameter is :"$2;

case -1
If i executed this script as 
sh test_1.sh

First Parameter is :

Second Parameter is :

Above two lines are empty because i have not given positional parameter values to script.

case-2
If i executed this script as 
sh test_1.sh 1 2

First Parameter is :1

Second Parameter is :2

case-2
If i executed this script as 
sh test_1.sh  2 **# here i given two spaces in between .sh and 2 and i thought 1st param is space and second param is 2 but**

First Parameter is :2

Second Parameter is :

The output looks like above. My first statement will apply here.

case-4
If i executed this script as 
sh test_1.sh " " 2

First Parameter is :

Second Parameter is :2

Here i kept space in quotes. Now i'm able to access the space value.

**This will be help full for you. But for your requirement please use below code.** 

In this you have **quote** the space value(""${empty_array[@]}"") which is coming from **an empty array**("${empty_array[@]}"). So you have to use additional quote to an empty array.

function display_empty_array_func() {
  local -a aug1=$1
  local -a aug2=${2:-no input}
  echo "array aug1 = ${aug1[@]}"
  echo "array aug2 = ${aug2[@]}"
}

declare -a empty_array=()

display_empty_array_func ""${empty_array[@]}"" "1"

The output is:
array aug1 =
array aug2 = 1

如果位置参数为空，shell脚本和shell函数将不考虑该值，而是将下一个非空值作为其值（位置参数值）。 如果我们想取空值，我们必须将该值用引号括起来

Ex: I'm having small script like 
cat test_1.sh
#!/bin/bash

echo "First Parameter is :"$1;

echo "Second Parameter is :"$2;

case -1
If i executed this script as 
sh test_1.sh

First Parameter is :

Second Parameter is :

Above two lines are empty because i have not given positional parameter values to script.

case-2
If i executed this script as 
sh test_1.sh 1 2

First Parameter is :1

Second Parameter is :2

case-2
If i executed this script as 
sh test_1.sh  2 **# here i given two spaces in between .sh and 2 and i thought 1st param is space and second param is 2 but**

First Parameter is :2

Second Parameter is :

The output looks like above. My first statement will apply here.

case-4
If i executed this script as 
sh test_1.sh " " 2

First Parameter is :

Second Parameter is :2

Here i kept space in quotes. Now i'm able to access the space value.

**This will be help full for you. But for your requirement please use below code.** 

In this you have **quote** the space value(""${empty_array[@]}"") which is coming from **an empty array**("${empty_array[@]}"). So you have to use additional quote to an empty array.

function display_empty_array_func() {
  local -a aug1=$1
  local -a aug2=${2:-no input}
  echo "array aug1 = ${aug1[@]}"
  echo "array aug2 = ${aug2[@]}"
}

declare -a empty_array=()

display_empty_array_func ""${empty_array[@]}"" "1"

The output is:
array aug1 =
array aug2 = 1

---

这可能会有帮助：这可能会有帮助：谢谢你的回答。我复制了你的样品并进行了测试，但结果没有改变。您是如何运行代码的？非常感谢。正如我所解释的，它正在工作。为您的参考PFA截图。感谢您再次回答。它在我的环境中仍然不起作用；GNUBash，版本4.3.42。但是请不要再介意这个问题了。我参考了Sundeep推荐的其他网站。谢谢您的回答。我复制了你的样品并进行了测试，但结果没有改变。您是如何运行代码的？非常感谢。正如我所解释的，它正在工作。为您的参考PFA截图。感谢您再次回答。它在我的环境中仍然不起作用；GNUBash，版本4.3.42。但是请不要再介意这个问题了。我参考了Sundeep推荐的其他网站。