Bash，文件中的grep语句

我用bash做了一个简单的答录机。基本上，如果你问候它，它会回敬你，但现在我在句子分析方面遇到了问题。 如果句子（$@）不止一个单词，则它将失败

if [[ "$@" = $(grep -Fx "$@" 'vocabulary/greeting') ]]
        then
            speak greeting
        elif [[ "$@" = $(grep -Fx "$@" 'vocabulary/appreciative') ]]

输出：

> hello
Sam:  Hi!
> how are you
grep: are: No such file or directory
grep: you: No such file or directory
grep: are: No such file or directory
grep: you: No such file or directory
grep: are: No such file or directory
grep: you: No such file or directory
grep: are: No such file or directory
grep: you: No such file or directory
grep: are: No such file or directory
grep: you: No such file or directory
Sam:  I don't understand.
> 

我该如何解决这个问题？ 我怎样才能捕捉到将来可能出现的此类错误？

使用

“$*”

而不是

“$@”

---

“$*”

是参数的字符串表示形式，而

“$@”

是一个数组。

虽然这可以用于OP，但请注意，这种方法会将所有空白占用为一个空格。因此，

/script Howareyou

将成为

/script Howareyou

。也许这正是OP想要的，为了更轻松地表现。

if [[ "$*" = "$(grep -Fx "$*" 'vocabulary/greeting')" ]]