如何从bash unix文件中剪切几行

我有一个文本文件：

你好 1. 2. 3. （未知行数） 你好 （未知行数） 你好 （未知行数） 你好 如何在前两个“hello”之间剪切行并将其保存到文件中？
因此，输出将是

1
2.
3.
（未知行数）

使用awk：

awk '$1=="Hello"{c++;next} c==1' oldfile | tee newfile

要发生第n次，请更改count变量：

awk -v count=1 '$1=="Hello"{c++;next} c==count' oldfile | tee newfile

---

下面是一个简单的bash脚本，它对我很有用：

#!/bin/bash
WORD="$1" # Word we look for, in this case 'Hello'
COUNT=0 # Internal counter for words
let MAXCOUNT="$2" # How many words to encounter before we stop
OUTPUT="$3" # Output filename
FILENAME="$4" # The file to read from
while read -r; do # read the file line by line
    [ "$MAXCOUNT" -le "$COUNT" ] && break; # if we reached the max number of occurances, stop
    if [[ "$WORD" = "$REPLY" ]]; then # current line holds our word
        let COUNT=$COUNT+1; # increment counter
        continue; # continue reading
    else # if current line is not holding our word
        echo "$REPLY" >> "$OUTPUT"; # print to output file
    fi
done <"$FILENAME" # this feeds the while with our file's contents

这就是我得到的：

$cat output.txt 
1
2
3
(unknown number of lines)

test.txt包含：

Hello
1
2
3
(unknown number of lines)
Hello
(unknown number of lines)
Hello
(unknow number of lines)
Hello

---

哦，谢谢=）如果要在最后两个Hello之间划行呢？应该是awk'$1==“Hello”{c++；next}c>2'oldfile>newfile吗？我有个问题。我用了一个#PS1变量来代替Hello，所以它是smth[user@hostnamepwd]#上面的代码不起作用，如果$WORD=$PS1怎么办？

Hello
1
2
3
(unknown number of lines)
Hello
(unknown number of lines)
Hello
(unknow number of lines)
Hello