Binary 如何在没有uudecode、base64或x/y/z/modem的情况下通过串行端口传输二进制文件？

我正在尝试通过一个小型嵌入式设备上的串行端口传输二进制文件，该设备没有uudecode、base64或x/y/z/modem UTIL

我为far所做的尝试是：

$ sudo picocom -l -r -b 921600 --send-cmd "ascii-xfr -snv" /dev/ttyS0
# cat > libdebug.so

$ cat libdebug.so | sudo tee /dev/ttyS0

---

但这会挂起我的设备。

实际上，我能做的就是以ascii模式上传我自己的uudecode.sh，然后我可以用它来解码我自己的二进制文件

以下是适用于ksh的脚本：

#!/bin/ksh

# uudecode in POSIX bourne shell
#
# *EXCRUCIATINGLY* SLOW!!!
#
# Taken from a reply to a blog post here:
# http://www.weeklywhinge.com/?p=108
#
# Copyright (c) 2015, Rafael Kitover <rkitover@gmail.com>
# Modified in 2018, Philippe Bouchard <philippeb8@gmail.com>
#
# Redistribution and use in source and binary forms, with or without
# modification, are permitted provided that the following conditions are met:
# * Redistributions of source code must retain the above copyright
# notice, this list of conditions and the following disclaimer.
# * Redistributions in binary form must reproduce the above copyright
# notice, this list of conditions and the following disclaimer in the
# documentation and/or other materials provided with the distribution.
#
# THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDER ``AS IS'' AND ANY
# EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
# WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE
# DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT HOLDER BE LIABLE FOR ANY
# DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES
# (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES;
# LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND
# ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
# (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS
# SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.

bs=0
while read -r t ; do
    if [ "$bs" -eq 1 ] ; then
        if [ "a$t" = "aend" ] ; then
            bs=2
        else
            set $(printf "%d " "'$(echo $t | cut -c1)" "'$(echo $t | cut -c2)" "'$(echo $t | cut -c3)" "'$(echo $t | cut -c4)" "'$(echo $t | cut -c5)" "'$(echo $t | cut -c6)" "'$(echo $t | cut -c7)" "'$(echo $t | cut -c8)" "'$(echo $t | cut -c9)" "'$(echo $t | cut -c10)" "'$(echo $t | cut -c11)" "'$(echo $t | cut -c12)" "'$(echo $t | cut -c13)" "'$(echo $t | cut -c14)" "'$(echo $t | cut -c15)" "'$(echo $t | cut -c16)" "'$(echo $t | cut -c17)" "'$(echo $t | cut -c18)" "'$(echo $t | cut -c19)" "'$(echo $t | cut -c20)" "'$(echo $t | cut -c21)" "'$(echo $t | cut -c22)" "'$(echo $t | cut -c23)" "'$(echo $t | cut -c24)" "'$(echo $t | cut -c25)" "'$(echo $t | cut -c26)" "'$(echo $t | cut -c27)" "'$(echo $t | cut -c28)" "'$(echo $t | cut -c29)" "'$(echo $t | cut -c30)" "'$(echo $t | cut -c31)" "'$(echo $t | cut -c32)" "'$(echo $t | cut -c33)" "'$(echo $t | cut -c34)" "'$(echo $t | cut -c35)" "'$(echo $t | cut -c36)" "'$(echo $t | cut -c37)" "'$(echo $t | cut -c38)" "'$(echo $t | cut -c39)" "'$(echo $t | cut -c40)" "'$(echo $t | cut -c41)" "'$(echo $t | cut -c42)" "'$(echo $t | cut -c43)" "'$(echo $t | cut -c44)" "'$(echo $t | cut -c45)" "'$(echo $t | cut -c46)" "'$(echo $t | cut -c47)" "'$(echo $t | cut -c48)" "'$(echo $t | cut -c49)" "'$(echo $t | cut -c50)" "'$(echo $t | cut -c51)" "'$(echo $t | cut -c52)" "'$(echo $t | cut -c53)" "'$(echo $t | cut -c54)" "'$(echo $t | cut -c55)" "'$(echo $t | cut -c56)" "'$(echo $t | cut -c57)" "'$(echo $t | cut -c58)" "'$(echo $t | cut -c59)" "'$(echo $t | cut -c60)" "'$(echo $t | cut -c61)")
            l=$(($1 -32 & 63 ))
            shift
            while [ $l -gt 0 ] ; do
                i0=$(($1 -32 & 63))
                shift
                i1=$(($1 -32 & 63))
                shift
                i2=$(($1 -32 & 63))
                shift
                i3=$(($1 -32 & 63))
                shift
                if [ $l -gt 2 ] ; then
                    echo -ne "\0$(($i0 >> 4))$(($i0 >> 1 & 7))$(($i0 << 2 & 4 | $i1 >> 4))\0$(($i1 >> 2 & 3))$(($i1 << 1 & 6 | $i2 >> 5))$(($i2 >> 2 & 7))\0$(($i2 & 3))$(($i3 >> 3 & 7))$(($i3 & 7))"
                    true
                elif [ $l -eq 2 ] ; then
                    echo -ne "\0$(($i0 >> 4))$(($i0 >> 1 & 7))$(($i0 << 2 & 4 | $i1 >> 4))\0$(($i1 >> 2 & 3))$(($i1 << 1 & 6 | $i2 >> 5))$(($i2 >> 2 & 7))"
                    true
                else
                    echo -ne "\0$(($i0 >> 4))$(($i0 >> 1 & 7))$(($i0 << 2 & 4 | $i1 >> 4))"
                    true
                fi
                l=$(($l-3))
            done
        fi
    elif [ $(echo $t | cut -c1-5) = "begin" ]; then
        bs=1
    fi
done

#/bin/ksh
#POSIX bourne shell中的uudecode
#
#*极度缓慢！！！
#
#摘自对以下博客帖子的回复：
# http://www.weeklywhinge.com/?p=108
#
#版权所有（c）2015，Rafael Kitover
#Philippe Bouchard于2018年修改
#
#以源代码和二进制形式重新分发和使用，带或不带
#如果满足以下条件，则允许进行修改：
#*源代码的重新分发必须保留上述版权
#请注意，此条件列表和以下免责声明。
#*二进制形式的重新分发必须复制上述版权
#请注意，此条件列表和中的以下免责声明
#随分发提供的文件和/或其他材料。
#
#本软件由版权所有者“原样”和任何
#明示或默示保证，包括但不限于
#针对特定用途的适销性和适用性的保证如下：
#否认。在任何情况下，版权持有人均不对任何
#直接、间接、附带、特殊、惩戒性或后果性损害
#（包括但不限于采购替代货物或服务；
#使用、数据或利润的损失；或业务中断），无论是何种原因造成的；以及
#任何责任理论，无论是合同责任、严格责任还是侵权责任
#（包括疏忽或其他）以任何方式因使用本文件而产生
#软件，即使已告知此类损坏的可能性。
bs=0
而read-rt；做
如果[“$bs”-等式1]；然后
如果[“a$t”=“aend”]；然后
bs=2
其他的
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