带传递数组的C函数家庭作业构建错误帮助初学者解决所需问题

我一直在网上搜索，试图解决我的构建错误。我很确定，一旦我修复了这些问题，我的程序就会正常运行，但由于我还无法编译我的代码，因此很难进行测试

任何建议都将不胜感激，是的，这是家庭作业。我是C语言的新手，我知道我可能犯了愚蠢的错误。我会把所有的回答作为一个学习的机会。代码如下。在错误发布之后

    // Program will take user input for student names and provide functions in
    //   order to sort  by first name, by last name
    // by score and a menu function.

    #include <stdio.h>
    #include <string.h>

    // Prototypes for functions
    int menu();
    void searchLast(char [][21], char [][21],float [], int);
    void searchFirst(char [][21], char [][21],float [], int);
    void sortLast(char [][21], char [][21],float [], int);
    void sortScore(char [][21], char [][21],float [], int);
    void printRecords(char [][21], char [][21],float [], int);

    int main()
    {
    int j,NumOfRecords, k = 0;
    char FirstN[15][21],LastN[15][21];
    float Score[15];
    int select = 0;

        // Asking for the number of records the students to add
    printf("How many records would you like to enter, minimum of 5, max of 15? "); G
    scanf("%d",&NumOfRecords);
    for( k = 0; k < NumOfRecords; k++) // Loop to take user input and save in appropriate 
                                           // array location 
    { 
        for(j=0;j<21;j++)
    {
        scanf("First name:  %s", &FirstN[k][j]);
        scanf("   Last Name: %s", &LastN[k][j]);
        scanf("   Score: %f", &Score[k]);
            printf("\n");
    }
    }


    select = menu();  // Calling menu function to assign selection to call the next function
printf("%d",select);  // checking to see that selection was passed to 'select'
while (select != 0)   // Sentinel loop to provide user with options to modify array output 
{
    if (select == 1)  // prints all records
    {
        printRecords(FirstN,LastN,Score,NumOfRecords);
    }
    if (select == 2) //Searches for First name and prints associated records
    {
        searchFirst(FirstN,LastN,Score,NumOfRecords);
    }
    if (select == 3) // Searches for last name and prints associated records
    {
        searchLast(FirstN,LastN,Score,NumOfRecords);
    }
    if (select == 4)  // Sorts records by score and prints associated records
    {
        sortScore(FirstN,LastN,Score,NumOfRecords);
    }
    if (select == 5)  // Sorts by last name and prints associated records
    {
        sortLast(FirstN,LastN,Score,NumOfRecords);
    }
    if (select == 0) // Exits program
        break;

    select = menu();
}

    return 0; 

    }

    int menu() // The menu function
    {
    int num;
    printf("Menu Options \n \n");
    printf("Print Records (press 1) \n");
    printf("Search by first name (press 2) \n");
    printf("Search by last name (press 3) \n");
    printf("Sort by score (press 4) \n");
    printf("Sort by last name (press 5) \n");
    printf("Exit the program (press 0) \n");
    printf("Please enter option number: ");
    scanf("%d", num); // Takes the selection to be passed out of the function
    return num; // Returns the selection to main
    }
    void searchLast(char FirstName[][21],char LastName[][21], float Scores[],int NumOfRecords)
    { 
    int j;
    char Lname[1][21];
    printf("Please enter last name to search for");
    for (j=0;j<20;j++)
{
    scanf("%s",Lname[0][j]);
}
    for(j=0;j<NumOfRecords;j++)
    {
    if(Lname[0] == LastName[j])
    {
        printf("%s %s %f",FirstName[j],LastName[j],Scores[j]);
    }
        }

    }


    void searchFirst(char FirstName[][21],char LastName[][21], float Scores[],int NumOfRecords)

    {
    int j;
    char Fname[1][21];
    printf("Please enter last name to search for");
    for (j=0;j<20;j++)
{
    scanf("%s",Fname[0][j]);
}
    for(j=0;j<NumOfRecords;j++)
{
    if(Fname[0] == FirstName[j])
    {
        printf("%s %s %f",FirstName[j],LastName[j],Scores[j]);
    }
} 
    }
    void sortLast(char FirstName[][21],char LastName[][21], float Scores[],int NumOfRecords)
    {
    int j,x = 0;
    int k;
    for(j = 0; LastName[j] < LastName[j+1] ; j++)
    {
    for(k = (j+1) ; k < NumOfRecords; k++)
        if (LastName[j] < LastName[k])
        {
            float temp = 0; // function attempts to sort Arrays saving string 
            char tempFirst; // values in a veriable to then be reassigned to 
            char tempLast;  // appropriate Array index.
            temp = Scores[j];
            Scores[j] = Scores[k];
            Scores[k] = temp;
            tempLast = LastName[j];
            LastName[j] = LastName[k];
            LastName[k] = tempLast;
            tempFirst = FirstName[j]
            FirstName[j] = FirstName[k];
            FirstName[k] = tempFirst;
    }
    void sortScore(char FirstName[15][21],char LastName[15][21], float Scores[],int NumOfRecords)

    {

int j,x = 0;
int k;
for(j = 0; Scores[j] < Scores[j+1] ; j++)
{
    for(k = (j+1) ; k < NumOfRecords; k++)
        if (Scores[j] < Scores[k])
        {
            float temp = 0;
            char tempFirst;
            char tempLast;
            temp = Scores[j];
            Scores[j] = Scores[k];
            Scores[k] = temp;
            tempLast = LastName[j];
            LastName[j] = LastName[k];
            LastName[k] = tempLast;
            tempFirst = FirstName[j]
            FirstName[j] = FirstName[k];
            FirstName[k] = tempFirst;
        }


}
printRecords(FirstName,LastName,Scores,NumOfRecords);
    }
    void printRecords(char FirstName[][21],char LastName[][21], float Scores[],int NumOfRecords)
    {
    int j = 0;
    for (j = 0; j < NumOfRecords ; j++)
    {
    printf("%s %s %f \n",FirstName[j],LastName[j],Scores[j]);

    }
    }

---

其中一个问题可能有很多：

这里有一个

char

数组（

LastName[][21]

）：

您试图在此处复制

char

数组：

LastName[j] = LastName[k];

这不是在C中复制字符串的方式。必须执行以下操作：

strncpy(LastName[j], LastName[k], 21);

编辑

---

我忘了提到：在C中，

char

数组如果以

NULL

（

'\0'

）结尾，就会变成字符串。您必须将字符串传递到strncpy才能正常工作。

tempLast=LastName[j]；我试图将姓氏字符串传递给一个变量，以便对数组进行重新排序。最好是将代码压缩为只显示不起作用的部分。对于未能关闭的循环，我在两个循环中有两个开括号。“我非常确定，一旦我修复了这些，我的程序将正常运行”——所有程序员都相信这一点。他们都错了。趁你还年轻，现在就改掉这种思维习惯。谢谢你的建议，我会铭记在心的。我已经让程序运行了，但是当它从菜单函数传递到打印记录函数时崩溃了，但是我想我已经找到了原因。我将重新组织我的代码，使菜单函数存在于main中，因为这不是程序的要求。因此，如果我要进行字符串复制，我需要将我的临时数组设置为接受字符数组，然后在重新排序中在这两个数组之间进行字符串复制？”字符模板[1][21]；int x=0；strncpy（TempLast[x]，LastName[j]，21）；'谢谢你消除了我的许多错误。

LastName[j] = LastName[k];

strncpy(LastName[j], LastName[k], 21);