书中的电源程序；c程序。朗；版本2，循环
我被“C编程语言”一书中的这一行代码困住了- “对于（p=1；n>0；--n）”-计数器从1运行到1以上，而步骤为-1。但是柜台是什么？n本身书中的电源程序；c程序。朗；版本2，循环,c,cycle,C,Cycle,我被“C编程语言”一书中的这一行代码困住了- “对于（p=1；n>0；--n）”-计数器从1运行到1以上，而步骤为-1。但是柜台是什么？n本身 （我曾经看到for（I=1；Ifor循环中的初始化表示p=1，而不是n=1，n已作为函数参数之一提供，并用作计数器。p是结果的累加器 写这篇文章的更清晰的方式可能是： int p = 1; while (n--) { p *= base; } return p; 这里的寓意是函数参数已经是局部变量，不需要为了它而创建一个重复的局部变量。修改函数参数非常
（我曾经看到for（I=1；Ifor循环中的初始化表示
p=1n=1npint p = 1;
while (n--) { p *= base; }
return p;
这里的寓意是函数参数已经是局部变量，不需要为了它而创建一个重复的局部变量。修改函数参数非常好。在每次迭代中
n--n1n0n>0for (p = 1; n > 0; --n)
^
| When n = 0, condition becomes 0 > 0 that is false
p=p*base；base*base*base*…n次p用于（p=1；n>0；--n）nn1pnint power（int base，int n）；result = power(3,2); // here base = 3, and n = 2
n1>0在第一个示例中，当您调用
power（3,2）；n21power（5,7）；n71pp1pbasep对于函数调用
power（3,2）；pcondition n > 0 is True because n is 2 (2 > 0).
p = p * base = 1 * 3 = 3
and p becomes 3.
Now --n decreases n to 1
condition n > 0 is True because n is 1 (1 > 0).
p = p * base = 3 * 3 = 9
and p becomes 9.
Now --n decreases n to 0
condition n > 0 is False because n is 0 (0 > 0).
condition false so loop breaks
condition n > 0 is True because n is 2 (2 > 0).
p = p * base = 1 * 3 = 3
and p becomes 3.
Now --n decreases n to 1
condition n > 0 is True because n is 1 (1 > 0).
p = p * base = 3 * 3 = 9
and p becomes 9.
Now --n decreases n to 0
condition n > 0 is False because n is 0 (0 > 0).
condition false so loop breaks
condition n > 0 is True because n is 2 (2 > 0).
p = p * base = 1 * 3 = 3
and p becomes 3.
Now --n decreases n to 1
condition n > 0 is True because n is 1 (1 > 0).
p = p * base = 3 * 3 = 9
and p becomes 9.
Now --n decreases n to 0
condition n > 0 is False because n is 0 (0 > 0).
condition false so loop breaks
p9int power(int base, int n)
nint p;
for (p = 1; n > 0; --n)
pint p = 1;
for(; n > 0; --n)
pfor(; n > 0; --n)
n0falsennp = p * base;
正如您在这里看到的，
pbase^nppnp