在读像1,2,3,4这样的行时,如何在c中正确地fscanf?
终端中的输出变为:在读像1,2,3,4这样的行时,如何在c中正确地fscanf?,c,file-io,input,output,C,File Io,Input,Output,终端中的输出变为:132714-275292160 32767 如何将其修复为:1234?您也需要读入整数之间的字符 void readFile(void) { FILE *file; int i; char line[100]; int testnr, testnr2, testnr3, testnr4; //testnr = 1; //testnr2 = 2; //testnr3 = 3; //testnr4 = 4;
132714-275292160 32767
如何将其修复为:
1234
?您也需要读入整数之间的字符
void readFile(void) {
FILE *file;
int i;
char line[100];
int testnr, testnr2, testnr3, testnr4;
//testnr = 1;
//testnr2 = 2;
//testnr3 = 3;
//testnr4 = 4;
file = fopen("test.txt","r");
fgets(line,500,file); // does not do anything with the first line
// read in 1,2,3,4
fscanf(file, "%i %i %i %i", &testnr, &testnr2, &testnr3, &testnr4);
printf("%i %i %i %i \n", testnr, testnr2, testnr3, testnr4);
fclose(file);
}
还要注意,fscanf
返回成功读取的次数。所以你可以做:
fscanf( file, "%i,%i,%i,%i", &nr, &nr2, &nr3, &nr4 );
您还需要读入整数之间的字符
void readFile(void) {
FILE *file;
int i;
char line[100];
int testnr, testnr2, testnr3, testnr4;
//testnr = 1;
//testnr2 = 2;
//testnr3 = 3;
//testnr4 = 4;
file = fopen("test.txt","r");
fgets(line,500,file); // does not do anything with the first line
// read in 1,2,3,4
fscanf(file, "%i %i %i %i", &testnr, &testnr2, &testnr3, &testnr4);
printf("%i %i %i %i \n", testnr, testnr2, testnr3, testnr4);
fclose(file);
}
还要注意,fscanf
返回成功读取的次数。所以你可以做:
fscanf( file, "%i,%i,%i,%i", &nr, &nr2, &nr3, &nr4 );
旁注:
char行[100]。。。fgets(第500行,文件)代码>是一个问题。建议fgets(行、行大小、文件)代码>-更安全。旁注:字符行[100]。。。fgets(第500行,文件)代码>是一个问题。建议fgets(行、行大小、文件)代码>-更安全。