文件读取并在C中存储为int
下面是一个场景。我有一个包含数字和字母x的文件中的矩阵。x表示没有路径出现。我试图读取一个文件并将其存储在int数组中。但效果不好。x的值不会更改为99999文件读取并在C中存储为int,c,C,下面是一个场景。我有一个包含数字和字母x的文件中的矩阵。x表示没有路径出现。我试图读取一个文件并将其存储在int数组中。但效果不好。x的值不会更改为99999 graph.txt 0 x x x x x x 0 x x x x x x 0 x x x x x x 0 x x x x x x 0 x x x x x x 0 this is the result. 0 2291852 1988293161 5507688 2291916 1988315945
graph.txt
0 x x x x x
x 0 x x x x
x x 0 x x x
x x x 0 x x
x x x x 0 x
x x x x x 0
this is the result.
0 2291852 1988293161 5507688 2291916 1988315945
3 1988315897 1238539516 3 1988897120 0
3 0 1988897120 2291908 1988273218 5508800
2291920 1988293445 19 2291976 1988390633 1988897120
1988390584 1238539576 2293452 0 2293256 2291936
1988339419 2293700 1988398293 1064569584 160 0
# define x 99999
int main(){
char filename[200]="";
char buffer[200];
int ch;
FILE * fileIn;
FILE * fileInn;
printf("\tEnter Filename> ");
scanf("%s", &filename); //Enter filename
if((fileIn = fopen(filename, "r")) == NULL) { //error filename
printf("File could not be opened. \n");}
else {
while(!feof(fileIn)){ //counts number of rows
ch = fgetc(fileIn);
if(ch == '\n') size+=1;
}
rewind(fileIn);
if(!(feof(fileIn))){ //puts the matrix in an array
int input[size][size];
for(a = 0; a<size; a++) {
for(b=0; b<size; b++) {
fscanf(fileIn, "%d", &input[a][b]);
}
}
printMatrix(input);
}else printf("EOF");
}
}
#定义x 99999
int main（）{
字符文件名[200]=“”；
字符缓冲区[200]；
int-ch；
文件*fileIn；
文件*fileInn；
printf（“\tEnter Filename>”）；
scanf（“%s”，&filename）；//输入文件名
如果（（fileIn=fopen（filename，“r”））==NULL）{//错误文件名
printf（“无法打开文件。\n”）；}
否则{
而（！feof（fileIn））{//统计行数
ch=fgetc（文件输入）；
如果（ch=='\n'）大小+=1；
}
倒带（文件输入）；
如果（！（feof（fileIn））{//将矩阵放入数组中
int输入[size][size]；
for（a=0；a#define x 9999
告诉编译器将符号x
视为程序中的值99999；它对如何处理从文件读取的字符没有影响
由于您明确地告诉fscanfxsscanfatoi定义x 99999xxsscanfatoi定义x 99999xxsscanfatoi定义x 99999x您可以将每个符号作为字符串读取，如果它是
xsscanfatoigetlinefgetsscanfstrtokstrtok'x'99999atoi（word）#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX_SIZE 1024
int main (int argc, char **argv) {
if (argc < 2) {
fprintf (stderr, "Error: insufficient input. Usage: %s input_file\n", argv[0]);
return 1;
}
char *line = NULL; /* forces getline to allocate space for buf */
ssize_t read = 0; /* number of characters read by getline */
size_t n = 0; /* limit number of chars to 'n', 0 no limit */
int idx = 0; /* simple index counter for array */
int row = 0; /* simple row counter index for array */
int *col = NULL; /* simple column counter for array */
int *array = NULL; /* array to hold integers read from file */
char *delim = " \n"; /* delimeter for strtok to parse line */
FILE *ifp = fopen(argv[1],"r");
if (!ifp)
{
fprintf(stderr, "\nerror: failed to open file: '%s'\n\n", argv[1]);
return 1;
}
array = calloc (MAX_SIZE, sizeof (array)); /* allocate MAX_SIZE elements */
col = calloc (MAX_SIZE, sizeof (col)); /* allocate MAX_SIZE elements */
while ((read = getline (&line, &n, ifp)) != -1) /* read each line in file with getline */
{
char *tmp = NULL; /* pointer to hold strtok results */
tmp = strtok (line, delim); /* first call to strtok using 'line' */
if (*tmp == 'x') /* test if tmp[0] = 'x' */
array [idx++] = 99999; /* if so, assign value of '99999' */
else
array [idx++] = atoi (tmp); /* if not, assign result of atoi (tmp) */
col[row]++; /* increase column count */
while ((tmp = strtok (NULL, delim)) != NULL) /* all remaining strtok calls use NULL */
{
if (*tmp == 'x') /* same tests as above */
array [idx++] = 99999;
else
array [idx++] = atoi (tmp);
col[row]++; /* increase column count */
}
row++; /* increase row count */
}
if (line) free (line); /* free memory allocated by getline */
int it = 0; /* simple index iterator */
while (col[it]) /* simple loop to validate columns */
{
if (it > 0)
if (col[it-1] != col[it])
{
fprintf (stderr, "Error: inconsistent colums of data read\n");
return 0;
}
it++;
}
printf ("\nProperties of array read from file '%s':\n\n", argv[1]);
printf (" elements: %d\n rows : %d\n cols : %d\n", idx, row, col[0]);
printf ("\nArray elements:\n\n");
for (it = 0; it < idx; it++) /* output information stored in array */
{
if ((it+1) % col[0] == 0 && it > 0)
printf (" %5d\n", array[it]);
else
printf (" %5d", array[it]);
}
printf ("\n");
if (array) free (array); /* free memory allocated to arrays */
if (col) free (col);
return 0;
}
$ cat dat/graph.txt
0 x x x x x
x 0 x x x x
x x 0 x x x
x x x 0 x x
x x x x 0 x
x x x x x 0
$ /bin/rgraph dat/graph.txt
Properties of array read from file 'dat/graph.txt':
elements: 36
rows : 6
cols : 6
Array elements:
0 99999 99999 99999 99999 99999
99999 0 99999 99999 99999 99999
99999 99999 0 99999 99999 99999
99999 99999 99999 0 99999 99999
99999 99999 99999 99999 0 99999
99999 99999 99999 99999 99999 0
从文件中读取数组的方法有多种。您的挑战增加了一个简单的复杂性，即必须从文件中读取字符和整数，然后根据字符是否表示数字或是否是单个字符“x”替换值“9”，将元素添加到数组中9999' 最简单的方法是使用面向行的输入从数据文件中一行一行地读取数据，然后根据需要解析每一行。我建议您与
getlinefgetsscanfstrtok