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C++ 求一个区域中最长的垂直向量_C++_Opencv - Fatal编程技术网

C++ 求一个区域中最长的垂直向量

C++ 求一个区域中最长的垂直向量,c++,opencv,C++,Opencv,我有一个轮廓,我需要找到它的长度和高度,定义为: 宽度是轮廓中最长的向量 高度是与宽度垂直的最长矢量 查找宽度实际上非常简单: std::vector<std::vector<cv::Point>> contours; cv::findContours(mask_in_rect, contours, cv::RETR_TREE, cv::CHAIN_APPROX_NONE); for (auto point1 : contours[0]) for (auto

我有一个轮廓,我需要找到它的长度和高度,定义为:

  • 宽度是轮廓中最长的向量
  • 高度是与宽度垂直的最长矢量
查找宽度实际上非常简单:

std::vector<std::vector<cv::Point>> contours;
cv::findContours(mask_in_rect, contours, cv::RETR_TREE, cv::CHAIN_APPROX_NONE);

for (auto point1 : contours[0])
    for (auto point2 : contours[0])
    {
        if (Wlongest.length() < Vector(point1, point2).length())
        {
            Wlongest = Vector(point1, point2);
        }
    }

但我不知道如何继续。

所以基本上只需要找到定向边界框。。。cv::rotatedRect(您的_点)
auto M = cv::getRotationMatrix2D({mask_in_rect.cols / 2.0f, mask_in_rect.rows / 2.0f}, -Wlongest.angle(), 1.0f);
auto Minv = cv::getRotationMatrix2D({mask_in_rect.cols / 2.0f, mask_in_rect.rows / 2.0f}, Wlongest.angle(), 1.0f);