C++ std::目标指针参数的线程错误
我有一个类似于以下的设置 A.hppC++ std::目标指针参数的线程错误,c++,c++14,stdthread,C++,C++14,Stdthread,我有一个类似于以下的设置 A.hpp #include <thread> class A { static void foo(char*, char*); void bar() { char* char_start = (char*) malloc(100 * sizeof(char)); char* char_end = char_start + (100 * sizeof(char)) - 1; std::
#include <thread>
class A {
static void foo(char*, char*);
void bar() {
char* char_start = (char*) malloc(100 * sizeof(char));
char* char_end = char_start + (100 * sizeof(char)) - 1;
std::thread t(foo, char_start, char_end);
t.join();
return;
}
};
int main() {
A.bar();
return 0;
}
我用
g++ -std=c++14 -pthread main.cpp
并获得:
usr/include/c++/4.9/functional: In instantiation of ‘struct std::_Bind_simple<void (*(long unsigned int*, char*, char*))(long unsigned int*, char*, char*, const bool&)>’:
/usr/include/c++/4.9/thread:140:47: required from ‘std::thread::thread(_Callable&&, _Args&& ...) [with _Callable = void (&)(long unsigned int*, char*, char*, const bool&); _Args = {long unsigned int*, char*, char*}]’
A.cpp:100:151: required from here
/usr/include/c++/4.9/functional:1665:61: error: no type named ‘type’ in ‘class std::result_of<void (*(long unsigned int*, char*, char*))(long unsigned int*, char*, char*, const bool&)>’
typedef typename result_of<_Callable(_Args...)>::type result_type;
^
/usr/include/c++/4.9/functional:1695:9: error: no type named ‘type’ in ‘class std::result_of<void (*(long unsigned int*, char*, char*))(long unsigned int*, char*, char*, const bool&)>’
_M_invoke(_Index_tuple<_Indices...>)
usr/include/c++/4.9/functional:在“struct std:_Bind_simple”的实例化中:
/usr/include/c++/4.9/thread:140:47:从'std::thread::thread(_-Callable&&,_-Args&&…[带_-Callable=void(&)(长无符号int*,char*,char*,const-bool&);_-Args={长无符号int*,char*,char}中需要
A.cpp:100:151:此处为必填项
/usr/include/c++/4.9/functional:1665:61:错误:在'class std::result_of'中没有名为'type'的类型
typedef typename result_of::type result_type;
^
/usr/include/c++/4.9/functional:1695:9:错误:在“class std::result_of”中没有名为“type”的类型
_M_invoke(_Index_tuple)
我无法解释这个错误。非常感谢您的帮助
编辑:很抱歉,我遗漏了foo
还有一个默认bool参数设置为false
。去掉默认参数,让我们对其进行编译。A.bar()
不是有效的语言构造。只能在A
的实例上调用bar()
,不能在typenameA
上调用
通过改变
A.bar();
到
通过提供
a::foo()
的虚拟实现,我能够构建并运行该程序。请创建一个。您问题中的代码示例不会产生错误。您使用的是哪个版本的g++?如果您尝试-std=c++11
,它会编译吗?@remyabel代码会按原样编译,使用@Columbo这是因为您更改了明显虚假的代码,即,为什么OP需要发布MCVE。@Columbo:代码完全不同。就像“我的屁股!值得解释为什么?
A a;
a.bar();