正在运行的if语句下只有一条语句 我用C++编写了一个程序，要求任何整数输入。程序仅在两次迭代后崩溃。代码如下： #include<iostream> int main() { int user_choice; std::cout <<"Please enter any number other than five: "; std::cin >> user_choice; while(user_choice != 5) { std::cout <<"Please enter any number other than five: "; std::cin >> user_choice; if(user_choice == 5) std::cout << "Program Crash"; break; } std::cout << "I told you not to enter 5!"; return 0; } #包括 int main（） { int用户选择； std：：不能由用户选择； while（用户选择！=5） { std：：不能由用户选择； 如果（用户选择==5） std:：cout

C++不尊重缩进；因此当您编写时：

if (counter == 10)
    std::cout << "Wow you still have not entered 5. You win!";
    user_choice = right_answer; 

此代码：

if (counter == 10)
    std::cout << "Wow you still have not entered 5. You win!";
    user_choice = right_answer;

---

if（条件）{statement1；statement2；}

@LogicStuff你能再解释一下你的评论吗你的代码还有更多，比如，你为什么要把

user\u choice

与

5

literal进行比较，而你应该做

user\u choice==right\u answer

？如果它们已经相等，为什么你觉得有必要将

right\u answer

分配给

user\u choice

？？你也已经硬编码了代码> 5代码/代码>输出消息……和代码>我告诉你不要进入5！< /Cord>永远是PRIMTEND.@ MR.Python绝对不，如果你还没有，得到一本C++书。你不能跳进C++和应用其他语言的构造…你会得到像.P.th.MR.Python之类的问题，我建议查一下“范围”。在那里。是的，学习这门语言能让你学得更好真是令人惊讶。

if (counter == 10)
    std::cout << "Wow you still have not entered 5. You win!";
user_choice = right_answer; 

if (counter == 10) {
    std::cout << "Wow you still have not entered 5. You win!";
    user_choice = right_answer; 
}

if (counter == 10)
    std::cout << "Wow you still have not entered 5. You win!";
    user_choice = right_answer;

if (counter == 10)
{
    std::cout << "Wow you still have not entered 5. You win!";
}
user_choice = right_answer;

if (counter == 10)
{
    std::cout << "Wow you still have not entered 5. You win!";
    user_choice = right_answer;
}